Answer:
Explanation:
ω = √k/m = √(33.9/0.28) = 11 rad/s
(a) maximum speed of the oscillating mass
vmax = ωA = 11(0.05) = 0.55 m/s
(b) speed of the oscillating mass when the spring is compressed 1.5 cm
The portion of total energy that is not spring potential is kinetic
½kA² - ½kx² = ½mv²
v = √(k(A² - x²)/m) = √(33.9(0.05² - 0.015²)/0.28 = 0.52482... ≈ 0.52 m/s
(c) speed of the oscillating mass as it passes the point 1.5 cm from the equilibrium position
Different wording, but same question as part (b) 0.52 m/s
(d) value of x at which the speed of the oscillating mass is equal to one-half the maximum value m
The portion of total energy that is not kinetic is spring potential
½kA² - ½mv² = ½kx²
x = √(kA² - m(vmax/2)²) / k) = √(33.9(0.05²) - 0.28(0.55/2)²) / 33.9)
x = 0.043305...≈ 4.3 cm
negative is answer a d l hope it helps you
Answer:
we know,
Power=work done\time taken
=10\2
=5 watt
Answer:
Explanation:
System of forces in balance
ΣFx = 0
ΣFy = 0
∑MA = 0
MA = F*d
Where:
∑MA : Algebraic sum of moments in the the point (A)
MA : moment in the point A ( N*m)
F : Force ( N)
d : Horizontal distance of the force to the point A ( N*m
Forces acting on the beam
T₁ = 620 N : Tension in cable 1 ,at angle of 30° with the vertical on the left
T₂ : Tension in cable 2, at angle of 50.0° with the vertical on the right.
W : Weight of the beam
x-y T₁ and T₂ components
T₁x= 620*sin30° = 310 N
T₁y= 620*cos30° = 536.94 N
T₂x= T₂*sin50°
T₂y= T₂*cos50°
Calculation of the T₂
ΣFx = 0
T₂x-T₁x = 0
T₂x=T₁x
T₂*sin50° = 310 N
T₂ = 310 N /sin50°
T₂ = 404.67 N
Calculation of the W
ΣFy = 0
T₂y+T₁y-W = 0
(404.67) *cos50° + 536.94 = W
W= 260.12+ 536.94
W= 797.06 N
Location of the center of gravity of the beam
∑MA = 0 , point (A) (point where the cable 2 of the right is located on the beam)
T₁y(5)-W(d) = 0
T₁y(5) = W(d)
d = T₁y(5)/W
d = 536.94(5) / 797.06
d = 3.37m
The center of gravity is located at 3.37m measured from the right end of the beam
Answer:
Vibrations are sent through the air to your ears.
Explanation:
Sound is a form of energy that is transmitted in compression and rare factions. Sound is a mechanical wave. All mechanical waves require a material medium for propagation.
The material medium for the propagation of sound is air. When the sound is produced by the speakers, the molecules of air are set into vibration and this vibration carries the sound from the speaker to your ears.