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AlexFokin [52]
3 years ago
6

How many moles of Al are needed to react completely with 1.8 mol of FeO?

Chemistry
1 answer:
Tju [1.3M]3 years ago
3 0
<span>1.8 × (2/3) = 1.2

brainliest please

</span>
You might be interested in
A car is traveling 83.3 kilometers per hour. What is its speed in miles per minute? One kilometer = 0.62 miles.
Leya [2.2K]
Hi. 2fouls! :)

First convert the number from kilometer to miles:
83.3*0.62
=51.646 miles

Now to find the miles per minutes,divide the miles per hours by 60 (the amount of minutes in an hour.)

51.646/60
=0.860766667

The car is travelling at a speed of 0.860766667 miles/minute.

Hope this helps.
-Benjamin

3 0
3 years ago
Read 2 more answers
A student wants to make a 0.150 M aqueous solution of silver (I) nitrate but only has 11.27 g of AgNO3. What volume of the 0.150
Usimov [2.4K]

Answer:

442.3 mL

Explanation:

Remember that Molarity is a measure of concentration in Chemistry and it's defined as the number of moles of the substance divided by liters of the solution:

M=\frac{Moles of substance X}{Volume of the solution}

Then, you can express 11.27 g of AgNO3 as moles of AgNO3 using the molar mass of the compound:

11.27 g AgNO_{3} *\frac{1 mole AgNO_{3}}{169.87 g AgNO_{3}} = 0.06634 moles AgNO_{3}

Then you can solve for the volume of the solution:

Volume of the solution=\frac{Moles of AgNO_{3}}{M} =\frac{0.06634 mol AgNO_{3}}{0.150 M} =0.4423 L = 442.3 mL

Hope it helps!

3 0
3 years ago
Help! giving brainliest
kirill [66]
It’s the 3d one


Good luckkkkkkkk
8 0
2 years ago
How did Rutherford discredit Thomson's plum pudding model of an atom?
Dafna1 [17]

Answer:

He conducted an experiment using gold foil and alpha particles.

Explanation:

Ernest Rutherford in 1911 performed the gold foil experiment which provided a better outlook to the structure of the atom. In his experiment, he bombarded a thin gold foil with alpha particles. Most of the alpha particles passed through the gold foil and just a few was deflected back.

This observation led Rutherford to propose the nuclear model of the atom in which an atom has a small positively charged centre and electrons moving round it.

5 0
2 years ago
Read 2 more answers
Calculate the grams of nitrogen in 125 g of NH4NO3
Marta_Voda [28]

Answer:

43.75 g of Nitrogen

Explanation:

We'll begin by calculating the mass of 1 mole of NH₄NO₃. This can be obtained as follow:

Mole of NH₄NO₃ = 1 mole

Molar mass of NH₄NO₃ = 14 + (4×1) + 14 + (3×16)

= 14 + 4 + 14 + 48

= 80 g/mol

Mass of NH₄NO₃ =?

Mass = mole × molar mass

Mass of NH₄NO₃ = 1 × 80 = 80 g

Next, we shall determine the mass of N in 1 mole of NH₄NO₃.

Mass of N in NH₄NO₃ = 2N

= 2 × 14

= 28 g

Thus,

80 g of NH₄NO₃ contains 28 g of N.

Finally, we shall determine the mass of N in 125 g of NH₄NO₃. This can be obtained as follow:

80 g of NH₄NO₃ contains 28 g of N.

Therefore, 125 g of NH₄NO₃ will contain = (125 × 28) / 80 = 43.75 g of N.

Thus, 125 g of NH₄NO₃ contains 43.75 g of Nitrogen

5 0
2 years ago
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