Ask question

Ask question

All categories

3 years ago

6

How many moles of Al are needed to react completely with 1.8 mol of FeO?

1 answer:

Tju [1.3M]3 years ago

3 0

<span>1.8 × (2/3) = 1.2

brainliest please

</span>

You might be interested in

Which of the following is a chemical change?

elena-s [515]

Hi I'm in Chemistry too this year,
I believe D is correct because usually physical changes are things like density, color or quantity.

3 0

3 years ago

Read 2 more answers

The process to separate the various components of a liquid mixture is called a fractional distillation true false

Black_prince [1.1K]

Decantation<span>Decantation is a process for the separation of mixtures, by removing a layer of liquid, generally one from which a precipitate has settled. The purpose may be either to produce a clean decant, or to remove undesired liquid from the precipitate (or other layers). Separate liquids
so it is false</span>

4 0

3 years ago

Read 2 more answers

a nickel atom (atomic symbol Ni) has an atomic number of 28 and has an atomic mass of 59. how many neutrons does it have ??

shusha [124]

Answer: 31 neutrons

Explanation:

8 0

3 years ago

Create a model of the atoms of a substance moving through the solid, liquid, and gas states.

hjlf

Hope this helpssssssnsnekwnwjwj

5 0

3 years ago

Read 2 more answers

A student prepares a 1.8 M aqueous solution of 4-chlorobutanoic acid (C2H CICO,H. Calculate the fraction of 4-chlorobutanoic aci

Kruka [31]

Answer:

Percentage dissociated = 0.41%

Explanation:

The chemical equation for the reaction is:

$C_3H_6ClCO_2H_{(aq)} \to C_3H_6ClCO_2^-_{(aq)}+ H^+_{(aq)}$

The ICE table is then shown as:

$C_3H_6ClCO_2H_{(aq)} \ \ \ \ \to \ \ \ \ C_3H_6ClCO_2^-_{(aq)} \ \ + \ \ \ \ H^+_{(aq)}$

Initial (M) 1.8 0 0

Change (M) - x + x + x

Equilibrium (M) (1.8 -x) x x

$K_a = \frac{[C_3H_6ClCO^-_2][H^+]}{[C_3H_6ClCO_2H]}$

where ;

$K_a = 3.02*10^{-5}$

$3.02*10^{-5} = \frac{(x)(x)}{(1.8-x)}$

Since the value for $K_a$ is infinitesimally small; then 1.8 - x ≅ 1.8

Then;

$3.02*10^{-5} *(1.8) = {(x)(x)}$

$5.436*10^{-5}= {(x^2)$

$x = \sqrt{5.436*10^{-5}}$

$x = 0.0073729 \\ \\ x = 7.3729*10^{-3} \ M$

Dissociated form of 4-chlorobutanoic acid = $C_3H_6ClCO_2^- = x= 7.3729*10^{-3} \ M$

Percentage dissociated = $\frac{C_3H_6ClCO^-_2}{C_3H_6ClCO_2H} *100$

Percentage dissociated = $\frac{7.3729*10^{-3}}{1.8 }*100$

Percentage dissociated = 0.4096

Percentage dissociated = 0.41% (to two significant digits)

3 0

3 years ago

Read 2 more answers