Answer:
For the Carnot air conditioner working as a heat pump between 63 and 100°F , It would transfer 3.125 Joules of heat for each Joule of electric energy supplied.
Explanation:
The process described corresponds to a Carnot Heat Pump. A heat pump is a devices that moves heat from a low temperature source to a relative high temperature destination. <em>To accomplish this it requires to supply external work</em>.
For any heat pump, the coefficient of performance is a relationship between the heat that is moving to the work that is required to spend doing it<em>.</em>
For a Carnot Heat pump, its coefficient of performance is defined as:
Where:
- T is the temperature of each heat deposit.
- The subscript H refers to the high temperature sink(in this case the outdoors at 100°F)
- The subscript L refers to the low temperature source (the room at 63°F)
Then, for this Carnot heat pump:
So for each 3.125 Joules of heat to moved is is required to supply 1 Joule of work.
A good diet. and exersise is the answer
Answer:
The electrical resistance of an object is a measure of its opposition to the flow of electric current.
Answer:
The velocity of the one thrown up will be the same as the second one
Explanation:
They will fall and hit the ground at the same time although they have the same velocity because object one although has double height it has initial velocity of zero
Answer:
The total amount of heat needed will be .
Explanation:
We will divide the calculation in two: First, the heat needed to melt the ice, and then the heat needed to warm the resulting liquid from 0°C to 37°C.
<em>i) </em>The fusion heat will be:
<em>ii)</em> The heat needed to warm the water from to will be:
So, the total amount needed will be the sum of these two results:
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