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3 years ago

30. A student correctly determined the

Physics

2 answers:

Lyrx [107]3 years ago

4 0

Answer: C

Explanation: Density= mass/volume

if dividing by same volume, need to increase mass in order to increase density.

same as 4=8/2 vs 8=16/2

increase numerator= increase in answer

diamong [38]3 years ago

3 0

Density of anything = (its volume) / (its mass)

If their volumes of are equal, then the rock with the greater density has a <em>greater mass. (C)</em>

It also weighs more than the other one, even though they have the same volume.

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What is the primary force that causes the seafloor to spread and continents to drift?

jekas [21]

The primary force would be Thermal Convection, it pushes it and thus makes continents drift.
-Hope that helps, Nexxmexx :3

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3 years ago

Which statement best describes the equation CaCO3 + 2HCl → CaCl2 + CO2 + H2O? CaCO3 is a reactant; it is present before the reac

Marat540 [252]

Answer:

CaCl2 is a reactant

Explanation:

Calcium carbonate (CaCO3) is a reagent, it is found on the left side, what is found on the right side are the products.

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3 years ago

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If 250 g of calcium chlorate decomposes into calcium chloride and oxygen, what mass of oxygen would be produced?

sineoko [7]

115.94g of O₂ are produced by 250g of Ca(ClO₃)₂

<u>Explanation:</u>

Ca(ClO₃)₂ -->CaCl₂ + 3O₂

One mole of calcium chlorate give three moles of oxygen.

Molar mass of calcium chlorate is

40+(35.5+16*3)*2 = 207g/mol

Molar mass of Oxygen = 32g

1 mole of calcium chlorate decomposes to form 3 moles of oxygen.

So,

207g of Ca(ClO₃)₂ produces 3 X 32g of O₂

250g of Ca(ClO₃)₂ will produce = $\frac{3 X 32}{207} X 250$

= 115.94g of O₂

Therefore, 115.94g of O₂ are produced by 250g of Ca(ClO₃)₂

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3 years ago

The beautiful Multnomah Falls in Oregon are approximately 206m high. If the Columbia river is flowing horizontally at 2.90m/s ju

zhenek [66]

Answer:

The overall velocity of the water when it hits the bottom is:

$v_f=63.61\ \frac{m}{s}$

Explanation:

Use the law of conservation of energy.

Call it instant [1] to the moment when the water is just before reaching the falls.

At this moment its height h is 206 meters and its velocity horizontally $v_i$ is $v_i = 2.90$ m/s.

At the instant [1] the water has gravitational power energy $E_g$

$E_g = mgh$

The water also has kinetic energy Ek.

$E_k = 0.5mv_i ^ 2$

Then the Total E1 energy is:

$E_1 = mgh + 0.5mv_i ^ 2$

In the instant [2] the water is within an instant of touching the ground. At this point it only has kinetic energy, since the height h = 0. However at time [2] the water has maximum final velocity $v_f$

So:

$E_2 = 0.5mv_f ^ 2$

As the energy is conserved then $E_1 = E_2$

$mgh + 0.5mv_i ^ 2 = 0.5mv_f ^ 2$

Now we solve for $v_f$ .

$gh + 0.5v_i ^ 2 = 0.5v_f ^ 2\\\\9.8(206) + 0.5(2.90) ^ 2 = 0.5v_f 2\\\\v_f^2 = \frac{9.8(206) + 0.5(2.90) ^ 2}{0.5}\\\\v_f = \sqrt{\frac{9.8(206) + 0.5(2.90) ^ 2}{0.5}}\\\\v_f=63.61\ \frac{m}{s}$

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3 years ago

Bohr's model of the atom included a positively charged _____ orbited by negatively charged _____. nucleus, protons nucleus, elec

alexgriva [62]

Electrons and neutrons

altho if I were you id check other sites. Hopefully I was able to help.. Have a great day :)

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3 years ago

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