Answer:
The pilot is 2214.22 miles from her starting position
Explanation:
Since the pilot is traveling at a constant speed of 635 mph, the total distance traveled can be easily found as follows:
There was a 10 degrees deviation, so the angle between the trajectory of both legs is 170 degrees.
The distance we need to find is that from the start of the first leg to the end of the second leg, those three distances form a triangle and since the side we're interested in is opposite to the 170 degrees angle, we can determine its length by the law of cosines:
The pilot is 2214.22 miles from her starting position
Answer:
v₂ = 97.4 m / s
Explanation:
Let's write the Bernoulli equation
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂
Index 1 is for tank and index 2 for exit
We can calculate the pressure in the tank with the equation
P = F / A
Where the area of a circle is
A = π r²
E radius is half the diameter
r = d / 2
A = π d² / 4
We replace
P = F 4 / π d²2
P₁ = 397 4 /π 0.058²
P₁ = 1.50 10⁵ Pa
The water velocity in the tank is zero because it is at rest (v1 = 0)
The outlet pressure, being open to the atmosphere is P1 = 1.13 105 Pa
Since the pipe is horizontal y₁ = y₂
We replace on the first occasion
P₁ = P₂ + ½ ρ v₂²
v₂ = √ (P1-P2) 2 / ρ
v₂ = √ [(1.50-1.013) 10⁵ 2/1000]
v₂ = 97.4 m / s
B) The transfer of energy from the hydrosphere to the atmosphere
This is because oceans are part of the hydrosphere. As the air warms it flows up into the atmosphere.
Hope this helps!
Answer:
20 m
Explanation:
Initial potential energy = final kinetic energy
mgh = 1/2 mv²
gh = 1/2 v²
h = v² / (2g)
Given v = 20 m/s and g = 10 m/s²:
h = (20 m/s)² / (2 × 10 m/s²)
h = 20 m
Answer:
(a) The current in the wire is 19.89 A
(b) The distance from the wire is 0.159 cm
Explanation:
Given;
magnetic field, B = 2.5 mT
diameter of the wire, d = 1 cm
radius of the wire, r = 0.5 cm = 0.005 m
(a) The current in the wire is calculated as;
(b) The distance from the wire where the magnetic field is 2.5 mT is calculated as;
