Question

1. According to Le Châtelier's principle, an increase in temperature will shift the equilibrium position toward the products in an endothermic reaction. (2 points)
True
False


2. According to Le Châtelier's principle, how will an increase in pressure affect a gaseous equilibrium system?

Shift it toward the products
Shift it toward the reactants
Shift it toward the side with higher total mole concentration
Shift it toward the side with lower total mole concentration

3. A chemical equilibrium between gaseous reactants and products is shown.

N2(g) + 3H2(g) ⇌ 2NH3(g)

How will the reaction be affected if the pressure on the system is decreased?

It will shift toward the reactant side as there is lower pressure on the reactant side.
It will shift toward the product side as there is higher pressure on the product side.
It will shift toward the reactant side as there are a greater number of moles of gas on the reactant side.
It will shift toward the product side as there are a fewer number of moles of gas on the product side.

Answer 1

Answer:

1. True

2. Shift it toward the side with lower total mole concentration

3. It will shift toward the product side as there are a fewer number of moles of gas on the product side.

Explanation:

1.

An endothermic reaction is reaction that will absorb energy from the surrounding arena. Increasing temperature will increase the heat of the system. Since the average heat of the surrounding is higher, it will be easier to do an endothermic reaction than exothermic, so this will shift the equilibrium position toward endothermic reaction.

2.

When pressure increase, the molecule will harder to expand. This mean reaction that produces more molecules will be harder to happen since it will take more room and increase the pressure further. This will make the equilibrium shift toward the side with lower total mole concentration since it will help to make more room, thus making the pressure lower.

3.

Remember that only the gas form will contribute to the pressure of the system. In this reaction, there are 3 kinds of gas: nitrogen, hydrogen, and ammonia. Since all form in this reaction gas, you can calculate them all.

On the left side, we have 1 nitrogen and 3 hydrogen so the total is 4.

On the right side, we have 2 ammonia so the total is 2.

When pressure decrease, the equilibrium will shift toward the side with lower total mole concentration, which is the ammonia side. So, the reaction will shift to the product side.