Answer:
B. 2
Explanation:
The reaction expression is given as:
_S + 3O₂ → 2SO₃
Now let us balanced the expression;
On the product side we have 2 moles of S
On the reactant side we should have 2moles of S
So, we put the coefficient 2 to balance the expression;
We have 6 moles oxygen on both sides
Answer:
Epx= - 21.4N/C
Epy= 19.84N/C
Explanation:
Electric field theory
The electric field at a point P due to a point charge is calculated as follows:
E= k*q/r²
E= Electric field in N/C
q = charge in Newtons (N)
k= electric constant in N*m²/C²
r= distance from load q to point P in meters (m)
Equivalences
1nC= 10⁻⁹C
known data
q₁=-2.9nC=-2.9 *10⁻⁹C
q₂=5nC=5 *10⁻⁹C
r₁=0.840m
Calculation of the electric field at point P due to q1
Ep₁x=0
Calculation of the electric field at point P due to q2
Calculation of the electric field at point P(0,0) due to q1 and q2
Epx= Ep₁x+ Ep₂x==0 - 21.4N/C =- 21.4N/C
Epy= Ep₁y+ Ep₂y=36.95 N/C-17.11N =19.84N/C
The value of cos θ in the given figure is 0.98.
<h3>
What is cosine of an angle?</h3>
The cosine of an angle is defined as the sine of the complementary angle.
The complementary angle equals the given angle subtracted from a right angle, 90.
cos θ = sin(90 - θ)
For example, if the angle is 30°, then its complement is 60°
cos 30 = sin(90 - 30)
cos 30 = sin 60
0.866 = 0.866
<h3>Cosine of an angle with respect to sides of a right triangle</h3>
cos θ = adjacent side / hypotenuse side
adjacent side of the given right triangle is calculated as follows;
adj² = 10² - 2²
adj² = 100 - 4
adj² = 96
adj = √96
adj = 9.8
cos θ = 9.8/10
cos θ = 0.98
Thus, the value of cos θ in the given figure is 0.98.
Learn more about cosine of angles here: brainly.com/question/23720007
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electric field lines are graphical presentation of electric field intensity
It is the graphical way to represent the electric field variation
If we draw the tangent to electric field line then it will give the direction of net electric field at that point
So whenever we draw the electric field lines of a charge distribution then it will always follow this basic properties
here we will always follow these basic properties of field lines
now as we can see that here two positive charges are placed nearby so the electric field must be like it can not intersect at any point because at intersection of two lines the direction of electric field not defined
As we have two directions of tangents at that point
So here the incorrect presentation is the intersection of two field lines which is not possible
