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natulia [17]
3 years ago
9

I need help someone please...

Physics
1 answer:
hram777 [196]3 years ago
8 0
D. Polar is your answer
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How do you find density of a regular solid?
Effectus [21]
Put the object or material on a scale to figure out<span> its mass. 3. Divide the mass by the volume to </span>figure out the density<span> (p = m / v). You may also need to know </span>how to calculate<span> the volume of a </span>solid s<span>o use the formula</span>
3 0
3 years ago
If a drop is to be deflected a distance d = 0.350 mm by the time it reaches the end of the deflection plate, what magnitude of c
Sloan [31]

Answer:

q = 4.87 X 10^ -14 C

Explanation:

As d=0.350 mm

The ink drop will be accelerated by the electric field between the plates:

a = F/m

d = a(D0 / v)^2 / 2 ...... 1

a = qE/m ............... 2

Substituting 2  into 1:

d = (qE/m)(D0 / v)^2 / 2

q = 2mdv^2 / [E(D0)^2]

q = 2(1.00e-11 kg)(3.50e-4 m)(15.0 m/s)^2 / [(7.70e4 N/C)(2.05e-2 m)^2]

q = 4.87e-14 C

6 0
3 years ago
Atoms that combine in What plsss
Brilliant_brown [7]

When atoms combine to form covalent bonds, the resulting collection of atoms or group of atoms is called a molecule.

<h3>How does atom combine?</h3>

Atoms can combine with each other through sharing of the electrons, donating the electrons etc. to make molecules.

When atoms combine by forming covalent bonds, the resulting collection of atoms is called a molecule. We can therefore say that a molecule is the simplest unit of a covalent compound.

Thus, when atoms combine to form covalent bonds, the resulting collection of atoms or group of atoms is called a molecule.

Learn more about combination of atoms here: brainly.com/question/5974633

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3 0
1 year ago
Electric fields are vector quantities whose magnitudes are measured in units of volts/meter (V/m). Find the resultant electric f
Vikentia [17]

Answer:

The resultant field will have a magnitude of 241.71 V/m, 30.28° to the left of E1.

Explanation:

To find the resultant electric fields, you simply need to add the vectors representing both electric field E1 and electric field E2. You can do this by using the component method, where you add the x-component and y-component of each vector:

E1 = 99 V/m, 0° from the y-axis

E1x = 0 V/m  

E1y = 99 V/m, up

E2 = 164 V/m, 48° from y-axis

E2x = 164*sin(48°) V/m, to the left

E2y = 164*cos(48°) V/m, up

Ex: E_{1_{x}} + E_{2_{x}} = 0 V/m - 164 *sin(48) V/m= -121.875 V/m\\Ey: E_{1_{y}} + E_{2_{y}} = 99 V/m + 164 *cos(48) V/m = 208.74 V/m\\

To find the magnitude of the resultant vector, we use the pythagorean theorem. To find the direction, we use trigonometry.

E_r = \sqrt{E_x^2 + E_y^2}= \sqrt{(-121.875V/m)^2 + (208.74V/m)^2} = 241.71 V/m

The direction from the y-axis will be:

\beta = arctan(\frac{-121.875 V/m}{208.74 V/m}) = 30.28° to the left of E1.

6 0
3 years ago
Starting from rest, a particle moving in a straight line has an acceleration of a = (2t - 6) m/s^2, where t is in seconds. What
hjlf

To solve this problem we will use the given expression and derive it in order to find the algebraic expressions of velocity and position. These equations will be similar to those already known in the cinematic movement but will be subject to the previously given function. We start deriving the equation for velocity

a = 2t-6

\frac{dv}{dt} = 2t-6

Integrate acceleration equation

\int dv = (2t-6)dt

v = 2(\frac{t^2}{2})-6t+C_1

v=t^2-6t+C_1

At t = 0, v = 0

Replacing,

0 = 0^2-6*0+C_1

Therefore the value of the first Constant is

C_1 = 0

The expression can be escribed as,

v = t^2-6t

Calculate the velocity after 6s,

v=t^2-6t

v = 6^2-6*6

v = 0m/s

Now using the same expression we can derive the equation for distance

v = t^2-6t

\frac{dx}{dt} =t^2-6t

\int dx = \int (t^2-6t)dt

x = \frac{t^3}{3}-6\frac{t^2}{2}+C_2

At t=0, x=0

0 = \frac{0^3}{3}-6(\frac{0^2}{2})+C_2

Therefore the value of the second constant is

C_2 = 0

x = \frac{t^3}{3}-\frac{6t^2}{2}

Calculate the distance traveled after 11 s

At  t=11s

x = \frac{11^3}{3}-6(\frac{11^2}{2})

x = 80.667m

6 0
3 years ago
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