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Mkey [24]
3 years ago
5

147.5 ml of ethyl alcohol (coefficient of volume expansion = 1120 x 10-6K-1) at a temperature of 273.1 K is measured into a 150.

0 ml glass beaker (whose coefficient of volumeexpansion is negligible by comparison). To what temperature does the beaker have to be warmed for it to be completely full (i.e. for the volume of the alcohol to reach 150.0 ml)?
Physics
1 answer:
marishachu [46]3 years ago
8 0

Answer:

288.2 K

Explanation:

\beta = Volumetric expansion coefficient = 1120\times 10^{-6}\ /K

T_i = Initial temperature = 273.1 K

T_f = Final temperature

v_0 = Original volume = 150 mL

Change in volume is given by

\Delta v=\beta v_0(T_f-T_i)\\\Rightarrow T_f=\frac{\Delta v}{\beta v_0}+T_i\\\Rightarrow T_f=\frac{150-147.5}{1120\times 10^{-6}\times 147.5}+273.1\\\Rightarrow T_f=288.2\ K

The temperature of the ethyl alcohol should be 288.2 K to reach 150 mL

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Answer:

Explanation:

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B = 22.25 s⁻¹

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a = g - B v

a = g at t = 0

c ) When v = .15

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= 9.8 - 3.31

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7 0
3 years ago
When an average force F is exerted over a certain distance on a shopping cart of mass m, its kinetic energy increases by 12mv2.
VMariaS [17]

Answer:

A)d=\dfrac{1}{2F}mv^2

B)\Delta KE'=2\times \dfrac{1}{2}mv^2

Explanation:

Given that

Force  = F

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\Delta KE=\dfrac{1}{2}mv^2

we know that

Work done by all the forces =change in the kinetic energy

a)

Lets distance = d

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W= F .d

F.d=ΔKE

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d=\dfrac{1}{2F}mv^2

b)

If the force become twice

F' = 2 F

F'.d=ΔKE'

2 F .d = ΔKE'                          ( F.d =Δ KE)

2ΔKE = ΔKE'

\Delta KE'=2\times \dfrac{1}{2}mv^2

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8 0
3 years ago
A current of 12 A flows for 20 minutes into an electric cooker. How much charge has the cooker used?
cluponka [151]
Time= 20 minutes= 20*60=1200 s
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7 0
3 years ago
Mary starts from her house, walks 80 meters south, and stops to chat with her aunt on the sidewalk. After chatting for a few min
marin [14]
Mary walks:
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t = 10 minutes = 600 seconds;
Average speed:
v = ( d 1 + d 2 + d 3 ) / t 
v = ( 80 m + 125 m + 45 m ) / 600 s
v = 250 m / 600 s
v = 0.4167 m/s ≈ 0.42 m/s
Answer:
E ) 0.42 meters/second
5 0
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If you run a complete loop around an outdoor track of length 400 m in 100 s, find your(a) average velocity and (b) average speed
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Answer:

a) 0 m/s

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The average velocity would end up being 0 because it is displacement over time and the displacement here is 0. However, speed is total distance over time which here is 400/100 so it is 4.

5 0
3 years ago
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