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omeli [17]
3 years ago
11

Why is atomic number the better way to organize the elements of the periodic table and not organizing by atomic mass?

Chemistry
1 answer:
kotegsom [21]3 years ago
4 0

A) The atomic mass can vary based on the number of neutrons the atoms of the same element have, so the atomic mass may not be in order.  Also, the atomic number is unique to each element.

Hope this helped!

You might be interested in
19
N76 [4]

Answer:

no. of moles of PbI₂ = 14 moles

Explanation:

Data Given:

no. of moles of HI = 28 moles

no. of moles of Pbl₂ = ?

Reaction Given

        Pb + 2HI -------→ Pbl₂ + H₂

Solution:

To solve this problem we have to look at the reaction

Reaction:

                  Pb  +  2HI   -------→  Pbl₂  +  H₂

                            2 mol          1 mol

So if we look at the reaction 2 mole of hydrogen iodide (HI) gives 1 moles of Lead iodide (PbI₂), then how many moles of Lead iodide (PbI₂) will be produced by 28 moles of hydrogen iodide (HI)

For this apply unity formula

                      2 mole of HI  ≅  1 moles of PbI₂

                      28 mole of HI  ≅  X moles of PbI₂

By Doing cross multiplication

                      moles of PbI₂ = 28 moles x 1 moles / 2 mole

                      moles of PbI₂ = 14 mole

28 mole of HI will produce 14 moles of PbI₂

4 0
3 years ago
Calculate the volume (in cm³) of 935 grams of steel. The density of steel is 7.8 g/cm³. Give your answer to 2 decimal places.
Effectus [21]

Answer:

<h2>119.87 cm³</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question we have

volume =  \frac{935}{7.8}  \\  = 119.871794...

We have the final answer as

<h3>119.87 cm³ to two decimal places</h3>

Hope this helps you

7 0
4 years ago
How much of a sample remains after three half-lives have occurred? 1/16 of the original sample 1/9 of the original sample 1/8 of
Drupady [299]
For this question, assume that you have 1 compound. This compound is divided in half once, so you are left with 0.5. That 0.5 that remains is divided in half again, this is the second half-life, and you are left with 0.25. The final half life involves dividing 0.25 in half, which means you are left with 0.125. For the answer to make sense, you need to know your conversions between decimals and fractions. To make it simple, if you have 0.125 and you times it by 8, you are left with your initial value of 1. Therefore, after three half-lives, you are left with 1/8th of the compound.
5 0
3 years ago
Read 2 more answers
Why is it difficult to accurately represent ammonia and methane on paper?
andrew-mc [135]

Answer:

The correct answer is because the molecular structure.

Explanation:

The difficulty of ammonia and methane to be represented on paper is due to the molecular structure. These compounds have a three-dimensional projection with defined angles. Ammonia presents angles of 109.5º between the atom of Nitrogen and those of Oxygen. The ammonia presents 107.8º between the oxygen atoms.

In the methane molecule, there is 109.5º between the hydrogen molecules and the carbon atom. This results in the need for a 3D representation of the molecule.

Have a nice day!

6 0
3 years ago
In which material would the particles be closest together?
Doss [256]
I think air but if wrong sorry
3 0
3 years ago
Read 2 more answers
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