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Agata [3.3K]
3 years ago
8

A bowling ball has a mass of 3.7kg, a moment of inertia of 0.340992kg*m^2, and a radius of 0.48m. It rolls along the lane withou

t slipping at a linear speed of 3.2m/s. What is the total kinetic energy of the rolling ball. Answer in units of J.
Physics
1 answer:
Rzqust [24]3 years ago
3 0
Kinetic energy due to linear motion:

E= \frac{1}{2}mv^2= \frac{1}{2}3.7(3.2)^2=18.944J

The angular velocity is found by 

v=r \omega

\omega =  \frac{v}{r}= \frac{3.2}{0.48}  =6.667rad/s

Kinetic energy due to rotational motion:

E= \frac{1}{2}I \omega^2 = \frac{1}{2}0.340992(6.667)^2=7.5776J
Then
E_{total}=18.944J+ 7.5776J=26.5216J


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Suppose of methane are burned in air at a pressure of exactly and a temperature of . Calculate the volume of carbon dioxide gas
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You push on a cart (18.0kg) at a 30 degree below horizontal angle. The coefficient of kinetic friction between the chair and the
podryga [215]

Given that force is applied at an angle of 30 degree below the horizontal

So let say force applied if F

now its two components are given as

F_x = Fcos30


F_y = Fsin30


Now the normal force on the block is given as

N = Fsin30 + mg

N = 0.5F + (18\times 9.8)

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now the friction force on the cart is given as

F_f = \mu N

F_f = 0.625(0.5F + 176.4)

F_f = 110.25 + 0.3125F

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3 years ago
A container of gas molecules is at a pressure of 2 atm and has amass density of 1.7 grams per liter. All of the molecules in the
Tpy6a [65]

Answer:

The speed of nitrogen molecule is 1.87 m/s.

Explanation:

Given that,

Pressure = 2 atm

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Using formula of idea gas

PV=nRT

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T=\dfrac{PM}{\rho R}

Put the value into the formula

T=\dfrac{2\times28}{1.7\times0.0821}

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We need to calculate the speed of nitrogen molecule

Using formula of RMS speed

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V_{rms}=\sqrt{\dfrac{3\times0.0821\times401.2}{28}}

V_{rms}=1.87\ m/s

Hence, The speed of nitrogen molecule is 1.87 m/s.

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3 years ago
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