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grigory [225]
3 years ago
12

Pleaseeeee help!!!!!!!!

Physics
1 answer:
Ainat [17]3 years ago
5 0
I did it last year. I thinks its A
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4 A magnet can exert a force of attraction or a force of repulsion on another magnet.
GenaCL600 [577]

Answer:

Push -repulsion

Pull - attraction

Explanation:

When two magnets are brought together, a push happens when a force of repulsion is experienced where the magnets move away from each other. This means their polarity is the same and this will cause the magnet to push away from each other.

When two magnets are brought together , a pull happens when a force of attraction is experienced where the magnets move close to each other. This means their polarity is different and thus causes the magnets to pull closer to each other.

7 0
3 years ago
Which of the following is a characteristic of a mixture
BARSIC [14]
I believe you forgot to add the choices. I will tell you some of the characteristics of mixtures and I hope you find one of them in the choices you have.

A mixture is a physical combination between two or more elements. No chemical reaction is involved in the formation of mixtures.
The components of the mixture can be separated using physical methods such as filtration, boiling and condensation.
Examples of mixtures include mixture of sugar and water or mixture of salt and sugar.
5 0
3 years ago
During the data transmission there are chances that the data bits in the frame might get corrupted. This will require the sender
aalyn [17]

1. Based on Scenario A, multiple frames will minimize re-transmission overhead and should be preferred in the encapsulation of packets.

2. Based on Scenario B, the encapsulation of packets should be in a single frame because of the high level of network reliability and accuracy.

 

<u>Justification:</u>

There will not be further need to re-transmit the packets in a highly reliable and accurate network environment, unlike in an environment that is very prone to errors.  The reliable and accurate network environment makes a single frame economically better.

Encapsulation involves the process of wrapping code and data together within a class so that data is protected and access to code is restricted.

With encapsulation, each layer:

  • provides a service to the layer above it
  • communicates with a corresponding receiving node

Thus, in a reliable and accurate network environment, single frames should be used to enhance transmission and minimize re-transmission overhead.  This is unlike in an environment that is very prone to errors, where multiple frames should rather be used to minimize re-transmission overhead.

Learn more about encapsulation of packets here: brainly.com/question/22471914

6 0
2 years ago
A wheel decelerates from 13.5 rad s−1 to 6.0 rad s−1 in 7 s. Calculate the angular displacement​
Igoryamba

Answer:

<em>Angular displacement=68.25 rad</em>

Explanation:

<u>Circular Motion</u>

If the angular speed varies from ωo to ωf in a time t, then the angular acceleration is given by:

\displaystyle \alpha=\frac{\omega_f-\omega_o}{t}

The angular displacement is given by:

\displaystyle \theta=\omega_o.t+\frac{\alpha.t^2}{2}

The wheel decelerates from ωo=13.5 rad/s to ωf=6 rad/s in t=7 s, thus:

\displaystyle \alpha=\frac{6-13.5}{7}

\displaystyle \alpha=\frac{-7.5}{7}

\displaystyle \alpha=-1.071 \ rad/s^2

Thus, the angular displacement is:

\displaystyle \theta=13.5*7+\frac{-1.071*7^2}{2}

\displaystyle \theta=94.5-26.25

\boxed{\displaystyle \theta=68.25\ rad}

Angular displacement=68.25 rad

3 0
3 years ago
A 1.0 meter long rod is held horizontally in the east-west direction on a distant planet and is dropped from a height of 1.23 m.
enyata [817]

Answer:

The induced emf between two end is 34.02 \times 10^{-5} V

Explanation:

Given:

Length of rod l = 1 m

Height h = 1.23 m

Magnetic field B = 6.93 \times 10^{-5} T

For finding induced emf,

  \epsilon = Blv

Where v = velocity of rod,

For finding the velocity of rod.

From kinematics equation,

 v^{2} = v_{o} ^{2} + 2gh

Where v_{o} = initial velocity, g = 9.8 \frac{m}{s^{2} }

   v = \sqrt{2gh}

   v = \sqrt{2 \times 9.8 \times 1.23}

   v = 4.91 \frac{m}{s}

Put the velocity in above equation,

   \epsilon = 6.93 \times 10^{-5} \times 1 \times 4.91

   \epsilon = 34.02 \times 10^{-5} V

Therefore, the induced emf between two end is 34.02 \times 10^{-5} V

6 0
2 years ago
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