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Likurg_2 [28]
3 years ago
9

How many of the following atomic particles does a neutral magnesium

Chemistry
1 answer:
VARVARA [1.3K]3 years ago
3 0

Answer:

\boxed{\text{12 p, 12 n, and 12 e}}

Explanation:

No atoms of Mg have a mass of 24.3050 u. That is the average mass of all the isotopes of Mg.

However, the most common isotope of Mg is ₁₂²⁴Mg (mass = 23.99 u)

The atomic number of Mg is 12. It has 12 protons.

The atomic mass of ²⁴Mg is 24. That's the total number of protons and neutrons.

 p + n = 24

12 + n = 24

       n = 12

An atom of ²⁴Mg has 12 neutrons.

If the atom is neutral, the number of electrons equals the number of protons.

e = p = 12

\text{An atom of }$^{24}$\text{Mg contains }\boxed{\textbf{12 p, 12 n, and 12 e}}

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mestny [16]

Answer:

metallic bond

because this diagram is electron gas theory which shows metallic bond

8 0
3 years ago
Calculate the oxidation number for carbon in CH4
Maksim231197 [3]

Answer:

+4

Explanation:

Oxidation number of neutral compound is 0

Oxidation number of hydrogen in methane is -1

C + (-1×4) = 0

C - 4 = 0

C = 4

8 0
2 years ago
What will the charge oxidiation state be for boron
artcher [175]

3+

So, compounds of boron contain boron in a positive oxidation state, generally +3. The sum of oxidation numbers of all constituent atoms of a given molecule or ion is equal to zero or the charge of the ion, respectively. ... In most of the stable compounds of boron, its oxidation number is +3

7 0
3 years ago
Use Boyle’s law to complete the following:
mixas84 [53]

Answer:

The answer to your question is: 0.25 l

Explanation:

Data

P1 = 1 atm

V1 = 0.5 l

P2 =2 atm

V2 = ?

T = constant

Formula

          V1P1 = V2P2

Clear V2 from the formula

            V2 = V1P1/P2

Substitution

            V2 = (0.5)(1)/2  substitution

                  = 0.25 l       result

3 0
3 years ago
A 0.105 L sample of an unknown HNO 3 solution required 35.7 mL of 0.250 M Ba ( OH ) 2 for complete neutralization. What is the c
oksano4ka [1.4K]

Answer: 0.17M

Explanation:

The equation for the reaction is :

2HNO3 + Ba(OH)2 —> Ba(NO3)2 + 2H2O

From the balanced equation, we obtain :

nA = mole of acid = 2

nB = mole of the base = 1

From the question, we obtain:

Va = Vol. Of acid = 0.105L

Ma = conc. Of acid =?

Vb = Vol of base = 35.7 mL = 0.0357L

Mb = conc. of base = 0.25M.

We solve for the conc. of the acid using:

MaVa / Mb Vb = nA / nB

(Ma x 0.105) / (0.25x0.0357) = 2

Cross multiply to express in linear form. We have:

Ma x 0.105 = 0.25 x 0.0357 x 2

Divide both side by 0.105. We have

Ma = (0.25 x 0.0357 x 2) / 0.105

Ma = 0.17M

Therefore the concentration of the acid(HNO3) is 0.17M

3 0
3 years ago
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