Question

Calculate the number of nitrogen atoms in 240 g of ammonium nitrate?

Answer 1

3.125 i believe is the answer

Answer 2

Answer : The number of nitrogen atoms are, $3.61\times 10^{24}$

Explanation : Given,

Mass of $NH_4NO_3$ = 240 g

Molar mass of $NH_4NO_3$ = 80 g/mole

First we have to calculate the moles of $NH_4NO_3$

$\text{Moles of }NH_4NO_3=\frac{\text{Mass of }NH_4NO_3}{\text{Molar mass of }NH_4NO_3}=\frac{240g}{80g/mole}=3mole$

As we know that $NH_4NO_3$ contains 2 number of nitrogen atoms, 4 number of hydrogen atoms and 3 number of oxygen atoms.

Now we have to calculate the number of atoms of nitrogen.

As, 1 mole of $NH_4NO_3$ contains $2\times 6.022\times 10^{23}$ number of nitrogen atoms

As, 3 mole of $NH_4NO_3$ contains $3\times 2\times 6.022\times 10^{23}=3.61\times 10^{24}$ number of nitrogen atoms

Therefore, the number of nitrogen atoms are, $3.61\times 10^{24}$