A controlled experiment is when scientests go throw thests to make an experiment
Answer:
El avión recorrió 45 km en los 180 s.
Explanation:
La relación entre velocidad, distancia y tiempo se da de la siguiente manera;
![Velocidad= \dfrac{Distancia}{Hora}](https://tex.z-dn.net/?f=Velocidad%3D%20%5Cdfrac%7BDistancia%7D%7BHora%7D)
Por lo cual los parámetros dados son los siguientes;
Velocidad = 900 km/h = 250 m / s
Tiempo = 180 s
Estamos obligados a calcular la distancia recorrida
De la ecuación para la velocidad dada arriba, tenemos;
Distancia recorrida = Velocidad pf viaje × Tiempo de viaje
Distancia recorrida = 900 km/h × 180 s = 900
Distancia recorrida = 900 km/h × 1 h/60 min × 1 min/60 s × 180 s = 45 km
Por lo tanto, el avión viajó 45 km en 180 s.
There would be very less percentage loss<span> of the kinetic energy during </span>the conversion<span> to internal energy, assuming that there is less air in the </span>surroundings<span>. Also, the friction will contribute to the conversion where if it is, the percentage loses is negligible.</span>
Answer:
![\ \text{m/s}](https://tex.z-dn.net/?f=%3C-0.5%2C%201.5%2C%20-3.5%3E%5C%20%5Ctext%7Bm%2Fs%7D)
Explanation:
= Velocity of one lump = ![3x+3y-3z](https://tex.z-dn.net/?f=3x%2B3y-3z)
= Velocity of the other lump = ![-4x+0y-4z](https://tex.z-dn.net/?f=-4x%2B0y-4z)
m = Mass of each lump = ![30\ \text{g}](https://tex.z-dn.net/?f=30%5C%20%5Ctext%7Bg%7D)
The collision is perfectly inelastic as the lumps stick to each other so we have the relation
![mu_1+mu_2=(m+m)v\\\Rightarrow m(u_1+u_2)=2mv\\\Rightarrow v=\dfrac{u_1+u_2}{2}\\\Rightarrow v=\dfrac{3x+3y-3z-4x+0y-4z}{2}\\\Rightarrow v=-0.5x+1.5y-3.5z=\ \text{m/s}](https://tex.z-dn.net/?f=mu_1%2Bmu_2%3D%28m%2Bm%29v%5C%5C%5CRightarrow%20m%28u_1%2Bu_2%29%3D2mv%5C%5C%5CRightarrow%20v%3D%5Cdfrac%7Bu_1%2Bu_2%7D%7B2%7D%5C%5C%5CRightarrow%20v%3D%5Cdfrac%7B3x%2B3y-3z-4x%2B0y-4z%7D%7B2%7D%5C%5C%5CRightarrow%20v%3D-0.5x%2B1.5y-3.5z%3D%3C-0.5%2C%201.5%2C%20-3.5%3E%5C%20%5Ctext%7Bm%2Fs%7D)
The velocity of the stuck-together lump just after the collision is
.
Answer:
the value of force, F=4.0N
Explanation:
Firstly, recall velocity-time equation
- v=u+at
- (4)=(2)+a(5)
- a=0.4m/s²
Secondly, recall the Newton's 2nd Law
- <em>F</em><em>=</em><em>ma</em>
- <em>F</em><em>=</em><em>(</em><em>1</em><em>0</em><em>)</em><em>(</em><em>0</em><em>.</em><em>4</em><em>)</em>
- <em>F</em><em>=</em><em>4</em><em>.</em><em>0</em><em>N</em>