The energy conversions in the Rude Goldberg device design is as follows:
- a quartz falls off from the roof: potential to kinetic
- the quartz hits and lift a soda bottle: kinetic to potential
- The soda bottle moves hits a battery: potential to kinetic
- a battery which slides along into a torch that lights up: chemical to light
<h3>What is a Rube Goldberg device?</h3>
A Rube Goldberg device uses a set of reactions that work in succession with one event triggering the next event in the form of a chain reaction until the final event is completed.
The Rude Goldberg device design is as follows:
The design is of a unit that produces light when a quartz falls off from the roof. It then hits a plastic soda bottle and its velocity is converted into potential energy used to lift a soda bottle. The soda bottle then on rising hits a battery which slides along into a torch which then light up.
In conclusion, Rude Goldberg devices shows various forms of energy conversion.
Learn more about Rude Goldberg Device at: brainly.com/question/10892506
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<u>Answer:</u> The chemical equations are given below.
<u>Explanation:</u>
The chemical equation for the reaction of lead nitrate and sodium hydroxide follows:
By Stoichiometry of the reaction:
1 mole of aqueous solution of lead nitrate reacts with 2 moles of aqueous solution of sodium hydroxide to produce 1 mole of solid lead hydroxide and 2 moles of aqueous solution of sodium nitrate.
The chemical equation for the reaction of lead hydroxide and hydroxide ions follows:
![Pb(OH)_2(s)+2OH^-(aq.)\rightarrow [Pb(OH)_4]^{2-}(aq.)](https://tex.z-dn.net/?f=Pb%28OH%29_2%28s%29%2B2OH%5E-%28aq.%29%5Crightarrow%20%5BPb%28OH%29_4%5D%5E%7B2-%7D%28aq.%29)
By Stoichiometry of the reaction:
1 mole of lead hydroxide reacts with 2 moles of aqueous solution of hydroxide ions to produce 1 mole of aqueous solution of tetra hydroxy lead (II) complex
Hence, the chemical equations are given above.
The atomic weight of the naturally occurring element would
simply be the weighted average of the two isotopes. Calculating:
atomic weight = (25.2 g / mol) * 0.801 + (29.4 g / mol) *
(1 – 0.801)
<span>atomic weight = 26.04 g / mol</span>
Explanation:
He used just the right amount of matter in water to get it to evaporate at a normal temperature and to condense into clouds for rain.
<h3>Answer:</h3>
Mole = 0.055 mol
<h3>Solution:</h3>
Step 1: Calculate Mass of Glucose in 200 mL solution:
As,
100 mL Solution contains = 5 g of Glucose
So,
200 mL Solution will contain = X g of Glucose
Solving for X,
X = (200 mL × 5 g) ÷ 100 mL
X = 10 g of Glucose
Step 2: Calculate Moles for 10 g of Glucose:
As,
Mole = Mass ÷ M.Mass
M.Mass of Glucose = 180 g.mol⁻¹
So,
Mole = 10 g ÷ 180 g.mol⁻¹
Mole = 0.055 mol
