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trapecia [35]
3 years ago
6

Which equations represent precipitation reactions? More than one can be chosen.

Chemistry
2 answers:
Ymorist [56]3 years ago
6 0

Answer is:

A. Na₂S + FeBr₂ → 2NaBr + FeS.

B. MgSO₄ + CaCl₂ → MgCl₂ + CaSO₄.

E. AgNO₃ + NaCl → AgCl + NaNO₃.

Iron sulfide (FeS) has low solubility in water.

Calcium sulfate (CaSO₄) has low solubility in water and it will form white precipitate.

Silver chloride (AgCl) has low solubility in water and it will form white precipitate.

Novay_Z [31]3 years ago
5 0

A. Na₂S + FeBr₂ → 2NaBr + FeS.

B. MgSO₄ + CaCl₂ → MgCl₂ + CaSO₄.

E. AgNO₃ + NaCl → AgCl + NaNO₃.

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How many moles are in 9.25E24 formulas units of sodium acetate?
Lelu [443]

Answer:

<h2>15.37 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{9.25 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 15.365448...

We have the final answer as

<h3>15.37 moles</h3>

Hope this helps you

5 0
3 years ago
Classify the statements pertaining to elements and compounds as either true or false
Volgvan

Yes Compounds are generally made of two or more atom or ion or species!

TRUE

3 0
3 years ago
Why do scientists study the natural world to find solutions to human problems?
Vlad1618 [11]

5e earth holds many answers to things we don’t know about.

5 0
3 years ago
Students learned that objects can exert forces on other objects without touching. Which three investigations will provide eviden
irinina [24]

Answer:

b

Explanation:

6 0
3 years ago
Determine the concentration of hydronium and hydroxide ions in a solution that has a pH of 1.6.
Veronika [31]

Answer:

The answer to your question is [H₃O⁺] = 0.025   [OH⁻] = 3.98 x 10⁻¹³

Explanation:

Data

[H⁺] = ?

[OH⁻] = ?

pH = 1.6

Process

Use the pH formula to calculate the [H₃O⁺], then calculate the pOH and with this value, calculate the [OH⁻].

pH formula

pH = -log[H₃O⁺]

-Substitution

1.6 = -log[H₃O⁺]

-Simplification

[H₃O⁺] = antilog (-1,6)

-Result

[H₃O⁺] = 0.025

-Calculate the pOH

pOH = 14 - pH

-Substitution

pOH = 14 - 1.6

-Result

pOH = 12.4

-Calculate the [OH⁻]

12.4 = -log[OH⁻]

-Simplification

[OH⁻] = antilog(-12.4)

-Result

[OH⁻] = 3.98 x 10⁻¹³

5 0
3 years ago
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