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3 years ago

Which equations represent precipitation reactions? More than one can be chosen.

Chemistry

2 answers:

Ymorist [56]3 years ago

6 0

Answer is:

A. Na₂S + FeBr₂ → 2NaBr + FeS.

B. MgSO₄ + CaCl₂ → MgCl₂ + CaSO₄.

E. AgNO₃ + NaCl → AgCl + NaNO₃.

Iron sulfide (FeS) has low solubility in water.

Calcium sulfate (CaSO₄) has low solubility in water and it will form white precipitate.

Silver chloride (AgCl) has low solubility in water and it will form white precipitate.

Novay_Z [31]3 years ago

5 0

A. Na₂S + FeBr₂ → 2NaBr + FeS.

B. MgSO₄ + CaCl₂ → MgCl₂ + CaSO₄.

E. AgNO₃ + NaCl → AgCl + NaNO₃.

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Calculate the density of a material that has a mass of 50.5g and a volume of 14.5cm3.

White raven [17]

Density = mass / volume = 50.5/14.5 = 3.48 $g/cm ^{3}$ .

4 0

3 years ago

Find the mass in grams of 4.52

Tanzania [10]

Answer:

Mass = 1274 .64 g it would be option C if it is converted into kilogram

1274 .64 / 1000 = 1.27 Kg

Explanation:

Given data:

Number of moles of C₂₀H₄₂ = 4.52 mol

Molar mass of carbon = 12 g/mol

Molar mass of hydrogen = 1.0 g/mol

Mass of C₂₀H₄₂ = ?

Solution:

Number of moles = mass / molar mass

Molar mass = 20× 12 + 42× 1.0 = 282 g/mol

Now we will put the values in formula:

Number of moles = mass / molar mass

4.52 mol = mass / 282 g /mol

Mass = 4.52 mol × 282 g/mol

Mass = 1274 .64 g

7 0

3 years ago

A ____________ star would have the hottest surface temperature.

Alexandra [31]

Answer:

Blue

Explanation:

If you look at a flame, blue is always at the bottom right? So that would be common sense that blue would be the hottest.

7 0

3 years ago

Read 2 more answers

In the reaction 2H2O (1)+ 2Cl^- (aq)= H2(g)+Cl2 (g)+ 2OH^-(aq), which substance is reduced?

Oksanka [162]

Answer:- C. H

Explanations:- Reduction is gain of electron. In other words we could say that decrease in oxidation number is reduction.

As per the rules, oxidation number of hydrogen in its compounds is +1(except metal hydrides) and the oxidation number of oxygen in its compounds is -2.

The oxidation number in elemental form is zero.

In $H_2O$ , the oxidation number of H is +1 and oxidation number of O is -2. Oxidation number of Cl in $Cl^-$ is -1. On product side, the oxidation number of hydrogen in $H_2$ is zero and in $OH^-$ the oxidation number of H is +1 and that of O is -2. Oxidation number of Cl in $Cl_2$ is 0.