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kati45 [8]
3 years ago
13

How to convert from fahrenheit to celsius

Physics
2 answers:
kaheart [24]3 years ago
8 0
The formula for Fahrenheit and Celsius conversion is 
T(°F)<span> = </span>T(°C)<span> × 1.8 + 32
where T is temperature in F or C ( Fahrenheit or Celsius whatever is the case)
</span>This means that keeping this FORMULA in mind we can add different values to it and  accordingly convert values from one to another.
Some examples of fahrenheit conversions to Celsius are :
32°F = 0°C  using F = (0 x 1.8) + 32


tensa zangetsu [6.8K]3 years ago
6 0

If you HAVE the temp in Fahrenheit and you want to know
what it would be in Celsius, plug the Fahrenheit temp that
you have into this formula:

                  C  =  5/9 (F - 32) .


If you HAVE the temp in Celsius and you want to know
what it would be in Fahrenheit, plug the Celsius temp
that you have into this formula:

                   F  =  1.8 C + 32 .

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1. Explique con sus palabras por qué el ser humano al nacer es un organismo inacabado, y que influencia ejercen en él las caract
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Answer:

Todo ser humano, al nacer, es un organismo inacabado en términos tanto físicos como psicoemocionales. Es decir, el humano, al nacer, lo hace sin la posibilidad de autosustentarse en el futuro inmediato: no puede caminar, expresarse, tener pensamiento analítico ni la capacidad de resolver las problemáticas que les afectan.

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7 0
3 years ago
2. a) If a bottle was filled with a liquid, tightly
kow [346]

Answer:

bottle might burst

Explanation:

because liquid inside will expand and exert pressure on walls of the bottle.

6 0
2 years ago
If the intensity of light that is incident on a piece of metal is increased, what else will be increased? Choose all that apply.
natka813 [3]

Answer:

explained

Explanation:

When the intensity of light is increased on a piece of metal only the number of electron ejected will increase because all other things independent of intensity of light.

Light below certain frequency will not cause any electron emission no matter how intense.

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7 0
3 years ago
When you irradiate a metal with light of wavelength 433 nm in an investigation of the photoelectric effect, you discover that a
sergij07 [2.7K]

Answer:

The right solution is:

(a) 2.87 eV

(b) 1.4375 eV

Explanation:

Given:

Wavelength,

= 433 nm

Potential difference,

= 1.43 V

Now,

(a)

The energy of photon will be:

E = \frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}

  = 4.59\times 10^{-19} \ J

or,

  = \frac{4.59\times 10^{-19}}{1.6\times 10^{-19}}

  = 2.87 \ eV

(b)

As we know,

⇒ Vq=\frac{hc}{\lambda}-\Phi_0

By substituting the values, we get

⇒ 1.43\times 1.6\times 10^{19}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}-\Phi_0

⇒                       \Phi_0=2.3\times 10^{-19} \ J

or,

⇒                            =\frac{2.3\times 10^{-19}}{1.6\times 10^{-19}}

⇒                            =1.4375 \ eV

5 0
3 years ago
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