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3 years ago

How to convert from fahrenheit to celsius

2 answers:

8 0

The formula for Fahrenheit and Celsius conversion is
T(°F) = T(°C) × 1.8 + 32
where T is temperature in F or C ( Fahrenheit or Celsius whatever is the case)
This means that keeping this FORMULA in mind we can add different values to it and accordingly convert values from one to another.
Some examples of fahrenheit conversions to Celsius are :
32°F = 0°C using F = (0 x 1.8) + 32

tensa zangetsu [6.8K]3 years ago

6 0

If you HAVE the temp in Fahrenheit and you want to know
what it would be in Celsius, plug the Fahrenheit temp that
you have into this formula:

C = 5/9 (F - 32) .

If you HAVE the temp in Celsius and you want to know
what it would be in Fahrenheit, plug the Celsius temp
that you have into this formula:

F = 1.8 C + 32 .

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A car changes velocity at a constant acceleration of 2.5m/s to reach 43.7m/s in 2.7 s how fast was the car moving when it began

Montano1993 [528]

The formula we can use in this case is:

v = v0 + a t

where v is final velocity, v0 is initial velocity, a is acceleration and t is time

So finding for v0:

v0 = v – a t

v0 = 43.7 – (2.5) 2.7

v0 = 36.95 m/s

8 0

3 years ago

Biologists use optical tweezers to manipulate micron-sized objects using a beam of light. In this technique, a laser beam is foc

vekshin1

Answer:

Explanation:

Part A) Using

light intensity I= P/A

A= Area= π (Radius)^2= π((0.67*10^-6m)/(2))^2= 1.12*10^-13 m^2

Radius= Diameter/2

P= power= 10*10^-3=0.01 W

light intensity I= 0.01/(1.12*10^-13)= 9*10^10 W/m^2

Part B) Using

I=c*ε*E^2/2

rearrange to solve for E= $\sqrt{$ ((I*2)/(c*ε))

c is the speed of light which is 3*10^8 m/s^2

ε=permittivity of free space or dielectric constant= 8.85* 10^-12 F⋅m−1

I= the already solved light intensity= 8.85*10^10 W/m^2

amplitude of the electric field E= $\sqrt{$ (9*10^10 W/m^2)*(2) / (3*10^8 m/s^2)*(8.85* 10^-12 F⋅m−1)

---> E= $\sqrt{$ (1.8*10^11) / (2.66*10^-3) = $\sqrt{$ (6.8*10^13) = 8.25*10^6 V/m

8 0

3 years ago

Does a feather fall as fast as a rock in a vacuum? If so why?

7nadin3 [17]

Answer:

No.

Explanation:

A feather is less dense and thus less force exerted while a rock is very dense thus exerting more force .

3 0

3 years ago

A golf ball reaches a height of 150 m before it stops rising and starts to fall to the ground. What is the golf balls speed (rou

artcher [175]

Answer:

v = 54 m/s

Explanation:

Given,

The maximum height of the flight of golf ball, h = 150 m

The velocity at height h, u = 0

The velocity of the golf ball right before it hits the ground, v = ?

Using the III equations of motion

v² = u² + 2gh

Substituting the given values in the above equation,

v² = 0 + 2 x 9.8 x 150 m

= 2940

v = 54 m/s

Hence, the speed of the golf ball right before it hits the ground, v = 54 m/s

4 0

3 years ago

Please help! I'm not sure what equation or the process to do this question.

lions [1.4K]

Answer:

The momentum is 1.94 kg m/s.

Explanation:

To solve this problem we equate the potential energy of the spring with the kinetic energy of the ball.

The potential energy $U$ of the compressed spring is given by

$U = \dfrac{1}{2} kx^2$ ,

where $x$ is the length of compression and $k$ is the spring constant.

And the kinetic energy of the ball is

$K.E = \dfrac{1}{2}mv^2.$

When the spring is released all of the potential energy of the spring goes into the kinetic energy of the ball; therefore,

$\dfrac{1}{2}mv^2 = \dfrac{1}{2}kx^2,$

solving for $v$ we get:

$v = x \sqrt{\dfrac{k}{m} }.$

And since momentum of the ball is $p=mv$ ,

$p =mx \sqrt{\dfrac{k}{m} }.$

Putting in numbers we get:

$p =(0.5kg)(0.25m) \sqrt{\dfrac{(120N/m)}{0.5kg} }.$

$\boxed{p=1.94kg\: m/s}$

5 0

3 years ago