Answer
613.63Hz
Explanation:
Fobs = (V/V-Vsource)Force
V=speed of sound
Fobs= (343/343-18.8)580
Fobs= 613.63Hz
Fobs = frequency observed
brainly.com/question/15339151
Answer: 6m/s
Explanation:
Using the law of conservation of momentum, the change in momentum of the bodies before collision is equal to the change in momentum after collision.
After collision, the two objects will move at the same velocity (v).
Let mA and mB be the mass of the two objects
uA and uB be their velocities before collision.
v be their velocity after collision
Since the two objects has the same mass, mA= mB= m
Also since object A is at rest, its velocity = 0m/s
Velocity of object B = 12m/s
Mathematically,
mAuA + mBuB = (mA+mB )v
m(0) + m(12) = (m+m)v
0+12m = (2m)v
12m = 2mv
12 = 2v
v = 6m/s
Therefore the speed of the composite body (A B) after the collision is 6m/s
The number of ocean waves that pass a buoy in one second is the frequency of the <span>wave. The crest of a transverse wave is its highest point. </span>
Answer:
This is the simplified definition.
Explanation:
The main goal of physics is to explain how things move in space and time and understand how the universe behaves.
