You can measure length wiht the greatest preciaion using a tape measure marked in milimeters.
Answer: C. milimeters.
Answer:
1.57 mol NaN₃
Explanation:
- 2 NaN₃ (s) → 2 Na (s) + 3 N₂ (g)
First we <u>use PV=nRT to calculate the number of N₂ moles that need to be produced</u>:
- R = 0.082 atm·L·mol⁻¹·K⁻¹
- T = 23.7 °C ⇒ 23.7 + 273.16 = 296.86 K
<u>Inputing the data</u>:
- 1.07 atm * 53.4 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.86
And <u>solving for n</u>:
Finally we <u>convert N₂ moles into NaN₃ moles</u>, using <em>the stoichiometric coefficients of the balanced reaction</em>:
- 2.35 mol N₂ *
= 1.57 mol NaN₃
Answer:
2051.9936 g
Explanation:
Mass = ?
Number of moles = 51.2 mol
The relationship between both quantities is given by the equation;
Number of moles = Mass / Molar mass
Solving for mass;
Mass = Number of moles * Molar mass
Mass = 51.2 * 40.078
Mass = 2051.9936 g
The number of grams of copper reacted is 445 grams
<u><em>calculation</em></u>
2Cu +O₂ → 2CuO
from equation above the mole ratio of Cu:CUO is 2:2 =1:1, therefore the moles of Cu is also= 7.00 moles
mass=moles x molar mass
from periodic table the molar mass of Cu= 63.5 g/mol
mass= 7.00 moles x 63.5 g/mol =445 grams