What element in the third period is a metalloid?

Suppose that at room temperature, a certain aluminum bar is 1.0000 m long. The bar gets longer when its temperature is raised. T

raketka [301]

Answer:

ΔL =0. 000312 m

Explanation:

Given that

At room temperature ( T = 25 ∘C) ,L= 1 m

$L=1+2.4\times 10^{-5}T$

So the length at 13.0 ∘C above room temperature

$L=1+2.4\times 10^{-5}T$

$L=1+2.4\times 10^{-5}\times 13$

L=1.000312 m

So the change in length

ΔL = 1.000312 - 1.0000 m

ΔL =0. 000312 m

4 0

3 years ago

The ability to navigate, hunt, and communicate by electric current in water most likely helps make up for the effect of dark, mu

fgiga [73]

The ability to navigate, hunt, and communicate by electric current in water most likely helps make up for the effect of vision. The answer to your question is VISION.

If fish live in a dark, murky water, that means that their sense of vision is affected. In dark, murky water they could not see anything. So, fish that lives in this kind of water developed the ability to o navigate, hunt, and communicate by electric current in water. This ability is known as electroreception. Among fish, electroreception is present in some sharks and rays, and electric eels.

I hope that this is the answer that you were looking for and it has helped you.

6 0

4 years ago

Which system sends nutrients to all the body's cells? excretory system nervous system circulatory system endocrine system

olga55 [171]

The circulatory system sends nutrients to the body's cells.

4 0

3 years ago

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A Hooke's law spring is mounted horizontally over a frictionless surface. The spring is then compressed a distance d and is used

zloy xaker [14]

Answer:

The compression is $\sqrt{2} \ d$ .

Explanation:

A Hooke's law spring compressed has a potential energy

$E_{potential} = \frac{1}{2} k (\Delta x)^2$

where k is the spring constant and $\Delta x$ the distance to the equilibrium position.

A mass m moving at speed v has a kinetic energy

$E_{kinetic} = \frac{1}{2} m v^2$ .

So, in the first part of the problem, the spring is compressed a distance d, and then launch the mass at velocity $v_1$ . Knowing that the energy is constant.

$\frac{1}{2} m v_1^2 = \frac{1}{2} k d^2$

If we want to double the kinetic energy, then, the knew kinetic energy for a obtained by compressing the spring a distance D, implies:

$2 * (\frac{1}{2} m v_1^2) = \frac{1}{2} k D^2$

But, in the left side we can use the previous equation to obtain:

$2 * (\frac{1}{2} k d^2) = \frac{1}{2} k D^2$

$D^2 = \frac{2 \ (\frac{1}{2} k d^2)}{\frac{1}{2} k}$

$D^2 = 2 \ d^2$

$D = \sqrt{2 \ d^2}$

$D = \sqrt{2} \ d$

And this is the compression we are looking for

3 0

4 years ago

Read 2 more answers

Describe the magnetic field in a bar magnet. Enter your answer in the spave provided.

neonofarm [45]

Answer:

The lines of the magnetic field from a bar magnet form closed lines. By convention, the field direction is taken to be outward from the North pole and into the South pole of the magnet. Permanent magnets can be made from ferromagnetic materials.

As can be visualized with the magnetic field lines, the magnetic field is strongest inside the magnetic material. The strongest external magnetic fields are near the poles. A magnetic north pole will attract the south pole of another magnet, and repel a north pole.

4 0

4 years ago