Answer:
2 meters
Explanation:
when you step away from a reflection you get farther
Answer:
The distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.
Explanation:
Given;
speed of the faster car, v₁ = 60 mi/h
speed of the slower car, v₂ = 55 mi/h
Let the distance traveled by the faster car when it is 15 mins ahead of the slower car = x miles
![\frac{x}{55} - \frac{x}{60} = \frac{15}{60}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B55%7D%20-%20%5Cfrac%7Bx%7D%7B60%7D%20%20%20%3D%20%5Cfrac%7B15%7D%7B60%7D)
Note: divide 15 mins by 60 to convert to hours for consistency in the units.
![\frac{x}{55} - \frac{x}{60} = \frac{15}{60}\\\\multiple \ through \ by \ 660\\\\12x - 11x = 165\\\\x = 165 \ miles](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B55%7D%20-%20%5Cfrac%7Bx%7D%7B60%7D%20%20%20%3D%20%5Cfrac%7B15%7D%7B60%7D%5C%5C%5C%5Cmultiple%20%5C%20through%20%5C%20by%20%5C%20660%5C%5C%5C%5C12x%20-%2011x%20%3D%20165%5C%5C%5C%5Cx%20%3D%20165%20%5C%20miles)
Therefore, the distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.
Answer:
x(t) = -8sin2t
Explanation:
See the attachment for solution
From my solving, we can deduce that w² = 4, and thus, w = 2
Therefore, the general solution is
x(t) = c1 cos2t + c2 sin2t
Considering the final variable, we can conclude that
x(0) = 0
x'(0) = -8 m/s
The final solution, thus
x(t) = -8sin2t
I guess it is a: seismic waves
-- Multiply each side of the formula by 2
-- Then divide each side by t
-- Then subtract V(i) from each side.