Answer:
Acceleration of the box is 4.9 m/s².
Explanation:
The free body diagram is shown below.
The weight of the body can be resolved into two mutually perpendicular components as shown. The force responsible for sliding motion of the box along the incline is due to
acting along the incline.
Therefore, as per Newton's second law of motion,
Net force = ![mass\times acceleration](https://tex.z-dn.net/?f=mass%5Ctimes%20acceleration)
Now, net force acting along the incline is only ![mg\sin \theta](https://tex.z-dn.net/?f=mg%5Csin%20%5Ctheta)
Therefore,
![mg\sin \theta=ma\\a=g\sin \theta](https://tex.z-dn.net/?f=mg%5Csin%20%5Ctheta%3Dma%5C%5Ca%3Dg%5Csin%20%5Ctheta)
Now, ![g=9.8\textrm{ and } \theta = 30](https://tex.z-dn.net/?f=g%3D9.8%5Ctextrm%7B%20and%20%7D%20%5Ctheta%20%3D%2030)
Therefore, the acceleration of the box is given as:
![a=9.8\times \sin(30)=9.8\times 0.5=4.9\textrm{ }m/s^{2}](https://tex.z-dn.net/?f=a%3D9.8%5Ctimes%20%5Csin%2830%29%3D9.8%5Ctimes%200.5%3D4.9%5Ctextrm%7B%20%7Dm%2Fs%5E%7B2%7D)
Acceleration of the box is 4.9 m/s².
Answer:
![27.164 lb/in^2](https://tex.z-dn.net/?f=27.164%20lb%2Fin%5E2)
Explanation:
We are given that
Gauge pressure at 3.4 degree Celsius,P=![24lb/in^2](https://tex.z-dn.net/?f=24lb%2Fin%5E2)
We have to find the gauge pressure in tire when the temperature rises to 26 degree Celsius.
Atmospheric pressure=![14.7lb/in^2](https://tex.z-dn.net/?f=14.7lb%2Fin%5E2)
![P_1=P+14.7=24+14.7=38.7lb/in^2](https://tex.z-dn.net/?f=P_1%3DP%2B14.7%3D24%2B14.7%3D38.7lb%2Fin%5E2)
K=273+Degree Celsius
![T_1=3.4+273=276.4 K](https://tex.z-dn.net/?f=T_1%3D3.4%2B273%3D276.4%20K)
![T_2=26+273=299K](https://tex.z-dn.net/?f=T_2%3D26%2B273%3D299K)
![P_2=\frac{P_1T_2}{T_1}](https://tex.z-dn.net/?f=P_2%3D%5Cfrac%7BP_1T_2%7D%7BT_1%7D)
![P_2=\frac{38.7\times 299}{276.4}](https://tex.z-dn.net/?f=P_2%3D%5Cfrac%7B38.7%5Ctimes%20299%7D%7B276.4%7D)
![P_2=41.864 lb/in^2](https://tex.z-dn.net/?f=P_2%3D41.864%20lb%2Fin%5E2)
Gauge pressure in tire when the temperature rises to 26 degree Celsius.=![41.864-14.7=27.164lb/in^2](https://tex.z-dn.net/?f=41.864-14.7%3D27.164lb%2Fin%5E2)
Answer: D. decreasing the temperature
Explanation:
A neutron is part of an atom
Answer:
Displacement from the starting position is 1224m
Explanation:
The object is moving at 120 meters per second, it does this for 10.2 seconds. Use multiplication to find the answer.
![120 \times 10.2 = 1224](https://tex.z-dn.net/?f=120%20%5Ctimes%2010.2%20%3D%201224)