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likoan [24]
4 years ago
6

You calculate the ___of a machine by dividing its __ by its work input and multiplying by 100

Physics
1 answer:
sweet [91]4 years ago
7 0
Efficiency= (Work Input/Work Output) x 100
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3 years ago
Equations E = 1 2πε0 qd z3 and E = 1 2πε0 P z3 are approximations of the magnitude of the electric field of an electric dipole,
tamaranim1 [39]

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The ratio of E_{app} and E_{act} is 0.9754

Explanation:

Given that,

Distance z = 4.50 d

First equation is

E_{act}=\dfrac{qd}{2\pi\epsilon_{0}\times z^3}

E_{act}=\dfrac{Pz}{2\pi\epsilon_{0}\times (z^2-\dfrac{d^2}{4})^2}

Second equation is

E_{app}=\dfrac{P}{2\pi\epsilon_{0}\times z^3}

We need to calculate the ratio of E_{act} and E_{app}

Using formula

\dfrac{E_{app}}{E_{act}}=\dfrac{\dfrac{P}{2\pi\epsilon_{0}\times z^3}}{\dfrac{Pz}{2\pi\epsilon_{0}\times (z^2-\dfrac{d^2}{4})^2}}

\dfrac{E_{app}}{E_{act}}=\dfrac{(z^2-\dfrac{d^2}{4})^2}{z^3(z)}

Put the value into the formula

\dfrac{E_{app}}{E_{act}}=\dfrac{((4.50d)^2-\dfrac{d^2}{4})^2}{(4.50d)^3\times4.50d}

\dfrac{E_{app}}{E_{act}}=0.9754

Hence, The ratio of E_{app} and E_{act} is 0.9754

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3 years ago
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I think it's B

Explanation:

sorry if im wrong

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