The type of bond connects the fatty acid will be " an ester bond".
Fatty acids could be joined to each of the three carbons of the glycerol molecule in a fat molecule by an ester bond that passes through into the oxygen atom. Three molecules are emitted during the establishment of the ester bond. Fats were also known as triacylglycerols as well as triglycerides because they are made consisting of three fatty acids and glycerol.
The three major nutrients in a diet may be carbohydrates, proteins, and fats. According to how many hydrogen bonds they contain, fats are classified as either saturated as well as unsaturated.
The type of bond connects the fatty acid will be " an ester bond".
Hence, the correct answer will be option (c)
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Answer:
ΔH = -110.5kJ
Explanation:
It is possible to obtain enthalpy of combustion of a particular reaction by the algebraic sum of similar reactions (Hess's law). Using:
1. C(s) + O₂(g) → CO₂(g) ΔH₁ = -393.5kJ
2. CO(g) + 1/2O₂(g) → CO₂(g) ΔH₂ = -283.0kJ
The sum of 1 -2 gives:
C(s) + <u>O₂(g)</u> + <u>CO₂(g)</u> → <u>CO₂(g)</u> + CO(g) + <u>1/2O₂(g)</u>
C(s) + 1/2O₂(g) → CO(g) ΔH = -393.5kJ - (-283.0kJ) =
<h3>ΔH = -110.5kJ</h3>
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Answer:
Mass = 46.52 g
Explanation:
Given data:
Mass of sodium phosphate react = 49.33 g
Mass of calcium phosphate produced = ?
Solution:
Chemical equation:
2Na₃PO₄ + 3Ca(NO₃)₂ → Ca₃(PO₄)₂ + 6NaNO₃
Number of moles of Na₃PO₄:
Number of moles = mass/molar mass
Number of moles = 49.33 g/ 163.94 g/mol
Number of moles = 0.300 mol
now we will compare the moles of Na₃PO₄ and Ca₃(PO₄)₂
Na₃PO₄ : Ca₃(PO₄)₂
2 : 1
0.300 : 1/2×0.300 = 0.15
Mass of Ca₃(PO₄)₂:
Mass = number of moles × molar mass
Mass = 0.15 mol × 310.14 g/mol
Mass = 46.52 g
Goldfish has more calories
Answer:
Explanation:
So ,SO2 molecules are covalent. ... Covalent is two non-metals sharing electrons while Ionic is a metal and a nonmetal where one takes an electron and changes both of the elements charges for example Nitrogen and Oxygen would be covalent while Iron and Oxygen would be Ionic. So ,SO2 molecules are covalent.