. Consider a sample of oxygen gas at 27° C with a volume of 9.55L at a pressure
Answer:
Bromine
Explanation:
To identify the gas, you first need to find the moles of the gas. You can do this using the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Constant (0.08206 atm*L/mol *K)
-----> T = temperature (K)
After converting mL to L and Celsius to Kelvin, you can plug the values into the equation and simplify to find the moles.
P = 1.98 atm R = 0.08206 atm*L/mol *K
V = 752 mL / 1,000 = 0.752 L T = 62 °C + 273.15 = 335.15 K
n = ? moles
PV = nRT
(1.98 atm)(0.752 L) = n(0.08206 atm*L/mol *K)(335.15 K)
1.48896 = n(27.5024)
0.0541 = n
You can identify the gas by determining the molar mass of the gas, which is specific to each element. The molar mass exists as a ratio that compares the mass per 1 mole.
Molar Mass = mass / moles
Molar Mass = 4.32 g / 0.0541 moles
Molar Mass = 79.8 g/mol
This molar mass is closest to the molar mass of bromine (79.904 g/mol).
After 3 half-lives, 125 grams of the parent isotope will remain.
