Answer:
Resistance of copper = 1.54 * 10^18 Ohms
Explanation:
<u>Given the following data;</u>
Length of copper, L = 3 kilometers to meters = 3 * 1000 = 3000 m
Resistivity, P = 1.7 * 10^8 Ωm
Diameter = 0.65 millimeters to meters = 0.65/1000 = 0.00065 m
Radius = 0.000325 m
To find the resistance;
Mathematically, resistance is given by the formula;
Where;
- P is the resistivity of the material.
- L is the length of the material.
- A is the cross-sectional area of the material.
First of all, we would find the cross-sectional area of copper.
Area of circle = πr²
Substituting into the equation, we have;
Area = 3.142 * (0.000325)²
Area = 3.142 * 1.05625 × 10^-7
Area = 3.32 × 10^-7 m²
Now, to find the resistance of copper;
<em>Resistance = 1.54 * 10^18 Ohms </em>
Answer:
just free your mind drink water and go outside take fresh air you will get answers.
Explanation:
This a best method to solve the answer.I hope it is helpful
Answer:
<em>Never</em>
Explanation:
In a reversible adiabatic process, there is not transfer of heat or matter between the system and its environment. An adiabatic reversible process is a process with constant entropy, i.e ΔQ=0. The internal energy is solely dependent on the work done either due to compression or expansion. So the entropy of the gas will never increase.
Answer:
a
Explanation:
A is the answers since pedmas
for parentheses exponents division multiplacation addition subtranction in that order
Answer:
P=- 88.41 KW
Negative sign indicates that power is given to the system.
Explanation:
Given that
P₂=500 KPa
T₂=130°C
V₂=100 m/s
mass flow rate ,m= 0.8 kg/s
Lets take inlet condition for air
T₁=25°C
P₁=100 KPa
V₁=0 m/s
We know that
Heat capacity for air Cp=1.005 KJ/kg.k
We know that for air change in enthalpy only depends only on temperature
Now from first law for open system
W=-110.52 KJ/kg
Shaft power P = m .W
P = -110.52 x 0.8
P=- 88.41 KW
Negative sign indicates that power is given to the system.