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Lostsunrise [7]
3 years ago
6

An 1647 w toaster, a 1592 w electric frying pan, and a 81 w lamp are plugged into the same outlet in a 120-v circuit. (the three

devices are in parallel when plugged into the same socket.). what current is drawn by the frying pan
Physics
1 answer:
yanalaym [24]3 years ago
6 0

Since all of the appliances ... and everything else in the house that's
plugged into a wall outlet ... are all in parallel, they don't have any
effect on each other.  They don't know about each other.  The
question asks about the frying pan, so the toaster and the lamp
have no effect  on the answer.

The frying pan has 120 V applied to it, and it produces 1592 watts
of heat.

Power = (voltage)·(current)

1592 watts = (120 v)·(current)

Divide each side by 120v:

Current = (1592 watts) / (120 volts)

Current = 13.27 Amperes
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Water flows through a horizontal nozzle in steady flow at the rate of 10m3/s. The inlet and outlet diameters are d1 = 0.5m and d2
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Answer:

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This problem of fluid mechanics let's start with the continuity equation to find the speed of water output

        Q = A v

        v = Q / A

The area of ​​a circle is

       A = π r² = π d² / 4

Let's look at the speeds at each point

       v₁ = Q / A₁ = Q 4 /π d₁²

       v₁ = 10 4 /π 0.5²

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       v₂ = Q / A₂

       v₂ = 10 4 /π 0.25²

       v₂ = 203.72 m / s

Now we can use Bernoulli's equation in the colon

       P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

Since the tube is horizontal y₁ = y₂. The output pressure is P₂ = Patm = 1.013 10⁵ Pa, let's clear

       P₁ = P2 + ½ rho (v₂² - v₁²)

      P₁ = 1.013 10⁵ + ½ 1000 (203.72² - 50.93²)

      P₁ = 1.013 10⁵ + 2.205 10⁷

      P₁ = 2.215 10⁷ Pa

la definicion de presion es

      P₁ = F₁/A₁

     F₁ = P₁ A₁

     F₁ = 2.215 10⁷ pi d₁²/4

     F₁ = 2.215 10⁷ pi 0.5²/4

     F₁ = 4.3 106 N

     

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