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IrinaK [193]
3 years ago
10

What happens when a substance absorbs light?

Physics
1 answer:
Anna11 [10]3 years ago
7 0
<span>One of three things the photon passes through unscathed, the photon gets absorbed by the electron of an atom and stays put, or the photon gets absorbed and a second generation photon is generated by that electron</span>
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Why do magnetic bodies lose their magnetic force?
stiks02 [169]

Answer:

Well a s the temperature increases, at a certain point called the Curie temperature, a magnet will lose its strength completely. So once the metal cools, its ability to attract magnets returns, though its permanent magnetism becomes weak. In general heat is the factor that has the most effect on permanent magnets.Explanation:

8 0
3 years ago
A liquid has a _______ volume and a _______ shape.
kakasveta [241]
Liquids have definite volume and indefinite shape.
7 0
3 years ago
A 3.0 kg box is at rest on a table. The static friction coefficient us between the box and table is 0.40, and
Oduvanchick [21]

While the box is at rest, the net vertical force acting on it is

∑ <em>F</em> = <em>n</em> - <em>w</em> = 0

where <em>n</em> = magnitude of the normal force (table pushing up on the box) and <em>w</em> = weight of the box. So we have

<em>n</em> = <em>w</em> = <em>mg</em> = (3.0 kg) (9.8 m/s²) = 29.4 N

The coefficient of static friction between the table and box is 0.40, so the maximum magnitude of static friction is

<em>f</em> = 0.40 <em>n</em> = 0.40 (29.4 N) = 11.76 N

which is to say, the box will not move unless a force larger than this is applied to the box.

10 N is of course smaller than 11.76 N, so the box would stay at rest, and its acceleration would remain 0 m/s².

7 0
3 years ago
a person throws a rock at 3 M/s down over the edge of a very tall cliff on Earth how far will the rock have fallen in 4 seconds
Nookie1986 [14]

The rock will be at 90.4 m from the top of the cliff.

<u>Explanation</u>:

The rock is thrown with the “initial velocity” 3 m/s. We need to find how much distance does the rock traveled in 4 seconds (t).

From the “kinematic equations” take

s=u t+\frac{1}{2} a t^{2}

Where, “s” is distance traveled, “u” initial velocity of the object, “t” time the object traveled and “a” acceleration due to gravity is 9.8 \mathrm{m} / \mathrm{s}^{2}.

Substitute the given values in the above formula,

s=3 \times 4+\frac{1}{2} \times 9.8 \times 4^{2}

s=12+\frac{1}{2} \times 9.8 \times 16

s=12+\frac{1}{2} \times 156.8

s=12+78.4

s=90.4

The rock is at height of 90.4 m from the top of the cliff.

6 0
3 years ago
calculate the potential energy of a 700kg squirrel that has leaped through the air with a height of 12m. (g=9.8m/s2)
Mnenie [13.5K]

Answer:

 P.E = 82320 joules

Explanation:

Given,

The mass of the squirrel, m = 700 Kg

The squirrel leaped to a height, h = 12 m

The acceleration due to gravity, g = 9.8 m/s²

The potential energy of a body is possessed by its height. It is given by the formula

                               P.E = mgh   joules

Substituting the values in the above equation

                               P.E = 700 Kg x 9.8 m/s² x 12 m

                                     = 82320 joules

The Potential Energy of the squirrel is, P.E = 82320 joules

8 0
2 years ago
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