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natulia [17]
3 years ago
9

A 120 kg quarterback is stationary in the "pocket" and hit by a defensive tackle with 4000 Newtons of force. What acceleration d

id the quarterback experience after being hit
Physics
1 answer:
Leni [432]3 years ago
6 0

Answer: 33.3 m/s^2

Explanation:

Here we need to use the second Newton's law.

F = m*a

Force equals mass times the acceleration.

Here we know that the force is F = 4000 N, and the mass is 120kg, then the acceleration must be:

4000 N = 120kg* a

a = (4000/120) m/s^2 = 33.3 m/s^2

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3 years ago
A vw beetle goes from 0 to 60 mi/h with an acceleration of 2.35 m/s^2.
Vlad1618 [11]
Part a.
u = 0, the initial velocity
v = 60 mi/h, the final velocity
a = 2.35 m/s², the acceleration.

Note that
1 m = 1609.34 m.
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v = u + at
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Answer: 11.4 s

Part b.
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Answer:  44.7 m/s²
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