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hichkok12 [17]
4 years ago
10

What is the chemical formula for iron (ii) oxide?​

Chemistry
2 answers:
ycow [4]4 years ago
5 0

The chemical formula for Iron ( II ) Oxide is :

FeO.

Hope this helps,

Davinia.

Bingel [31]4 years ago
4 0

Answer: FeO

Explanation:

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When the following aqueous solutions are mixed together, a precipitate forms. Balance the net ionic equation in standard form fo
rewona [7]

<u>Answer:</u>

<u>For (a):</u> The balanced net ionic equation is 2Ag^{+}(aq)+S^{2-}(aq)\rightarrow Ag_2S(s) and the sum of coefficients is 4

<u>For (b):</u> The balanced net ionic equation is Pb^{2+}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s) and the sum of coefficients is 4

<u>For (c):</u> The balanced net ionic equation is Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s) and the sum of coefficients is

<u>For (d):</u> The balanced net ionic equation is Ba^{2+}(aq)+2OH^{-}(aq)\rightarrow Ba(OH)_2(s) and the sum of coefficients is 4

<u>For (e):</u> The balanced net ionic equation is Ag^{+}(aq)+Cl^{-}(aq)\rightarrow AgCl(s) and the sum of coefficients is 3

<u>Explanation:</u>

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

  • For (a): Sodium sulfide and silver nitrate

The balanced molecular equation is:

Na_2S(aq)+2AgNO_3(aq)\rightarrow 2NaNO_3(aq)+Ag_2S(s)

The complete ionic equation follows:

2Na^{+}(aq)+S^{2-}(aq)+2Ag^+(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+Ag_2S(s)

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

2Ag^{+}(aq)+S^{2-}(aq)\rightarrow Ag_2S(s)

Sum of the coefficients = [2 + 1 + 1] = 4

  • For (b): Lead(II) nitrate and sodium chloride

The balanced molecular equation is:

2NaCl(aq)+Pb(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+PbCl_2(s)

The complete ionic equation follows:

2Na^{+}(aq)+2Cl^{-}(aq)+Pb^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+PbCl_2(s)

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

Pb^{2+}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s)

Sum of the coefficients = [2 + 1 + 1] = 4

  • For (c): Calcium nitrate and potassium carbonate

The balanced molecular equation is:

K_2CO_3(aq)+Ca(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+CaCO_3(s)

The complete ionic equation follows:

2K^{+}(aq)+CO_3^{2-}(aq)+Ca^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2K^+(aq)+2NO_3^-(aq)+CaCO_3(s)

As potassium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)

Sum of the coefficients = [1 + 1 + 1] = 3

  • For (d): Barium nitrate and sodium hydroxide

The balanced molecular equation is:

2NaOH(aq)+Ba(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+Ba(OH)_2(s)

The complete ionic equation follows:

2Na^{+}(aq)+2OH^{-}(aq)+Ba^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+Ba(OH)_2(s)

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions

The net ionic equation follows:

Ba^{2+}(aq)+2OH^{-}(aq)\rightarrow Ba(OH)_2(s)

Sum of the coefficients = [2 + 1 + 1] = 4

  • For (e): Silver nitrate and sodium chloride

The balanced molecular equation is:

NaCl(aq)+AgNO_3(aq)\rightarrow NaNO_3(aq)+AgCl(s)

The complete ionic equation follows:

Na^{+}(aq)+Cl^{-}(aq)+Ag^{+}(aq)+NO_3^{-}(aq)\rightarrow Na^+(aq)+NO_3^-(aq)+AgCl(s)

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

Ag^{+}(aq)+Cl^{-}(aq)\rightarrow AgCl(s)

Sum of the coefficients = [1 + 1 + 1] = 3

8 0
3 years ago
Why are metals good conductors of heat?
loris [4]

Answer: A. The free-moving electrons transmit heat quickly.

Explanation:

3 0
3 years ago
HURRY PLEASE
katrin2010 [14]

Answers:

Question 1:

The diagram for gallium will have flat, horizontal lines at <u><em>30 and 2204</em></u><em> </em>°C.

Questoin 2:

The diagram for methane will have a <u><em>diagonal </em></u>line representing the <u><em>liquid phase</em></u> between -183°C and -162°C.

Question 3:

For gold, the boiling point corresponds to the y-value at <u><em>2856</em></u><u> </u>°C of <u><em>the top horizontal line</em></u>

Question 4.

For nitrogen, the line at -210°C will be<u><em> flat</em></u>, which represents <u><em>the change from a solid to a liquid</em></u>

Explanations:

Question 1:

The diagram for gallium will have flat, horizontal lines at <u><em>30 and 2204</em></u><em> </em>°C.

The table shows that the melting point of gallium is 30°C and its boiling point is 2204°C.

<em>Melting point</em> is the temperature at which the substace changes its state from<em> solid to liquid</em>. During that change, <em>the temperature</em> of the substance <em>does not change</em>, because the heat supplied is used to accomplish the phase change. So, the temperature is constant and that means <em>that portion of the diagram is flat</em>.

The same is valid during<em> boiling</em>: the temperature remains constant while the substance is passing<em> from liquid to gas</em> at the boiling point.

Questoin 2:

The diagram for methane will have a <u><em>diagonal </em></u>line representing the <u><em>liquid phase</em></u> between -183°C and -162°C.

Between the <em>melting</em> (-183°C) and<em> boiling</em> (-162°C) points of methane, its temperature will increase more or less linearly, which is represented with a <em>diagonal</em> (slant) <em>line</em> between those points. During this interval the heat is used to <em>increase the temperature</em> and no phase of change happens.

Question 3:

For gold, the boiling point corresponds to the y-value at <u><em>2856</em></u><u> </u>°C of <u><em>the top horizontal line</em></u>

<u><em></em></u>

The table shows that the<em> boiling point</em> of gold is 2,856°C.

In a <em>temperature-vs.-time diagram</em> the<em> temperature is represented on the vertical axis (y-value)</em> and the time is represented on the horizontal axis.

Since, the temperature of the substance does not change during <em>boiling,</em> the line during the time that this change of phase is happening is flat. And since this temperatue is higher than the melting temperature, this is the <em>top horizontal line in the diagram</em>.

Question 4.

For nitrogen, the line at -210°C will be<u><em> flat</em></u>, which represents <u><em>the change from a solid to a liquid</em></u>

<u><em></em></u>

The table shows that the <em>melting point </em>of nitrogen is -210°C, that means that the temperature will remain constant at -210°C while the substance is absorbing heat to pass from solid to liquid.

<u>In conclusion, you must remember that all the phase changes, melting (from solid to liquid), freezing (from liquid to solid), boilng (from liquid to gas), and condensing (from gas to liquid) happens at constant temperature, and so the </u><em><u>temperature - vs. - time diagrams </u></em><u>show flat lines (constant y-values) during those intervals of time.</u>

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I think it's oxygen gas

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