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Murrr4er [49]
3 years ago
8

Which goal incorporates most of the criteria required for a SMART goal?

Engineering
1 answer:
STatiana [176]3 years ago
8 0

Answer:

e

Explanation:

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A digital filter is given by the following difference equationy[n] = x[n] − x[n − 2] −1/4y[n − 2].(a) Find the transfer function
slega [8]

Answer:

y(z) = x(z) - x(z) {z}^{ - 2}  -  \frac{1}{4} y(z) {z}^{ - 2}  \\ y(z) + \frac{1}{4} y(z) {z}^{ - 2} = x(z) - x(z) {z}^{ - 2} \\ y(z) (1 + \frac{1}{4}{z}^{ - 2}) = x(z)(1 - {z}^{ - 2}) \\  h(z) = \frac{y(z)}{x(z)}  =  \frac{(1 + \frac{1}{4}{z}^{ - 2})}{(1 - {z}^{ - 2})}

The rest is straightforward...

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3 years ago
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irina1246 [14]

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3 0
3 years ago
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Which option identifies what Maria must pay attention to while creating her sketches in the following scenario?
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5 0
3 years ago
9. An embankment having a volume of 320,000 yd is to be constructed from local borrow. The dry unit weight and moisture content
tatuchka [14]

Answer:

correct option is (B) 315,500

Explanation:

given data

volume = 320,000 yd³ = 8640000 ft³

dry unit weight = 106 pcf

moisture content = 18.2%

total unit weight = 122 pcf

moisture content = 16.7%

to find out

volume of borrow lyd needed

solution

first we get here weight of material that is

weight = volume × unit weight

weight = 8640000 ×  122

weight = 1054080000 lb

that weight is weight of water + weight of solid so

0.167 × weight is weight of water + weight of solid ) = 1054080000 lb

and weight of solid = \frac{1054080000}{1.167}

weight of soil solid is = 903239075 pound

and weight of water = 150840925 pound

so volume of soil = 903239075 ÷ 106 lb/ft³ = 8521123.34 ft³

and volume required =  8521123.34 ft³ ÷ 27 ft³ =  315597.161 yd³

volume required = 315500 yd³

so correct option is (B) 315,500

3 0
3 years ago
1. What most commonly joins the structural panels of
notka56 [123]

Answer:

a

Explanation:

becasue it is

5 0
3 years ago
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