3 years ago

What is the importance of a reference point when looking at motion

1 answer:

8 0

<span>It is important to use a fixed common reference point on your work peace or drawing to avoid cumulative error</span>

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Which property of the sound wave changes when the volume is increased on a radio?.

ch4aika [34]

Answer:

amplitude

Explanation:

When we increase the volume of a sound, the amplitude of the wave is increased. The frequency of a wave is related to its pitch. If the pitch is high, then the frequency of the wave is high. This means that the wave will looked squashed on an oscilloscope trace.

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2 years ago

Constants A capacitor is connected across an ac source that has voltage amplitude 59 0 V and frequency 77 0 Hz Part C What is th

Vladimir79 [104]

Answer:

$C = 1.77 \times 10^{-4} F$

Explanation:

As we know that in AC circuit we have

$V = i x_c$

here we have

V = 59 V

i = 5.05 A

so we will have

$x_c = \frac{59}{5.05}$

$x_c = 11.68 ohm$

also we know that

$x_c = \frac{1}{\omega C}$

here we will have

$11.68 = \frac{1}{(2\pi 77)C}$

$C = 1.77 \times 10^{-4} F$

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3 years ago

Air can be humidified by passing through a long tube whose inside diameter is lined with a wick saturated with liquid water. The

Oduvanchick [21]

Answer:

IV because the process of water is equal to 5,8 to 783253.23 to the hendroxagram of 4.

Explanation:

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3 years ago

Bacteria prefer a dry environment to a damp or moist environment. False True

mariarad [96]

Answer:

false

Explanation:

cause bacteria prefers moist and damp environment

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3 years ago

Read 2 more answers

At a distance D from a very long (essentially infinite) uniform line of charge, the electric field strength is 1000 N/C. At what

Alla [95]

Answer:

The correct option is (a).

Explanation:

We know that, the E is inversely proportional to the distance as follows :

$E=\dfrac{k}{d^2}$

We can write it as follows :

$\dfrac{E_1}{E_2}=(\dfrac{d_2}{d_1})^2$

Put all the values,

$\dfrac{1000}{2000}=(\dfrac{d_2}{d})^2\\\\\sqrt{\dfrac{1000}{2000}}=(\dfrac{d_2}{D})\\\\0.7071=\dfrac{d_2}{d}\\\\d_1=0.7071D\\\\d_1=\dfrac{D}{\sqrt2}$

So, the correct option is (a).

5 0

3 years ago