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tatiyna
3 years ago
10

What is the importance of a reference point when looking at motion

Physics
1 answer:
Cloud [144]3 years ago
8 0
<span>It is important to use a fixed common reference point on your work peace or drawing to avoid cumulative error</span>
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Chemical equations should be balanced so that they demonstrate the law of conservation of mass. Which of the following statement
faust18 [17]

Answer:

The products must contain the same numbers and types of atoms

7 0
3 years ago
450 nm of light falls on a single slit of width 0.30 mm. What is the angular width of the central diffraction peak
Andre45 [30]

Angular width is 3 x 10^-3

Let D be the distance between source and screed d the distance between coherent source then for central diffraction maxima,

where λ is wavelength

Given:

λ = 450 nm = 450×10^−9m

d = 0.3x10^−3m, D = 1m

W = 2 x 450×10^−9/0.3x10^−3*1

To Find:

Angular width

Solution: The width of the central maxima is nothing but the difference between the positions of the first two minima. Hence we will use the expression for the position of minima and accordingly obtain the expression of the width of central maxima and secondary maxima

θ = W/D

θ = 2 x 450×10^−9/0.3x10^−3*1/1 = 3 x 10^-3

Hence, angular width is 3 x 10^-3

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4 0
2 years ago
Number of waves that pass a given point in one second
Studentka2010 [4]
<em>number of waves that pass a given point in one second is called <u>frequency..</u></em>
5 0
4 years ago
A 2 kg object is
Mademuasel [1]
NO net force is required to keep a moving object moving in a straight
line at a constant speed.  In fact, if you apply ANY force to it, in ANY
direction, then its speed, its direction, or both must change, and its
velocity won't be uniform any more. 

I know we never see this in our daily life.  Whenever we see an object
moving, it always stops.  That's because the net force on it is never zero ...
there's always some gravity or some friction acting on it.  That's what you
have to put up with when you live on Earth.
8 0
3 years ago
A 75.0 kg sailor climbs a 28.3 m rope ladder at and angle of 45.0degrees with the mast. how much work did he do?
sladkih [1.3K]
W = m · g · h
h = 28.3 m · sin 45° = 28.3 m · 0.707 = 20 m
g = 9.8 m/s²
W = 75 kg · 9.8 m/s² · 20 m
Answer:
W = 14,700 J = 14.7 kJ 

8 0
4 years ago
Read 2 more answers
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