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Umnica [9.8K]
3 years ago
14

6. Rank the following in terms of increasing kinetic energy:

Physics
2 answers:
bogdanovich [222]3 years ago
5 0
I'm doing dis greatest to least

1.C
2.A
3.D
4.B
Alborosie3 years ago
4 0

Answer:

B < D < A < C

Explanation:

Kinetic energy depends on the mass and the square of the velocity of the body. A body in motion has kinetic energy.

A. m = 12000 kg

v = 15 m/s

K.E. = 0.5 mv²

      = 0.5 (12000 kg) (15 m/s)²

      = 1,350,000 J

B. m = 10,000 kg

v = 0

K.E. = 0 J

C. m = 15 kg

v = 1000 m/s

K.E.=0.5 mv²

      = 0.5 (15 kg) (1000 m/s)²

      = 7,500,000 J

D. m = 100 kg

v = 5 m/s

K.E.=0.5 mv²

      = 0.5 (100 kg) (5 m/s)²

      = 250 J

In increasing order of kinetic energy:

B < D < A < C

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The skateboarder has a mass of 100 kg. When traveling downward from E to D, he reaches a velocity of 11 m/s. Calculate his kinet
patriot [66]

6050 J is the kinetic energy at D

<u>Explanation:</u>

In physics, the object's kinetic energy (K.E) defined as the energy it possesses during movement. It can be defined as the required work to accelerate a certain body weight in order to rest at a certain speed. When the body receives this energy as it speeds up (accelerates), it retains this energy unless speed varies. The equation is given as,

           K . E=\frac{1}{2} \times m \times v^{2}

Where,

m - mass of an object

v - velocity of the object

Here,

Given data:

m  = 100 kg

v = 11 m/s

By substituting the given values in the above equation, we get

            K . E=\frac{1}{2} \times 100 \times(11)^{2}=\frac{1}{2} \times 100 \times 121=\frac{12100}{2}=6050\ \mathrm{J}

6 0
3 years ago
A vacuum cleaner produces sound with a measured sound level of 75.0 dB. (a) What is the intensity of this sound in W/m2? W/m2 (b
jonny [76]

Answer:

Part a)

I = 3.16 \times 10^{-5} W/m^2

Part b)

P_o = 0.162 Pa

Explanation:

Part a)

Level of sound = 75 dB

now we know that

L = 10 Log\frac{I}{I_0}

here we know that

I_0 = 10^{-12} W/m^2

now we have

75 = 10 Log(\frac{I}{10^{-12}})

I = 3.16 \times 10^{-5} W/m^2

Part b)

Intensity of sound wave is given as

I = \frac{1}{2}\rho A^2\omega^2 c

here we know that

A = \frac{P_o}{Bk}

so we have

I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c

I = \frac{1}{2}\rho P_o^2 \frac{c^3}{B^2}

now we know

\rho = 1.2 kg/m^3

c = 340 m/s

B = 1.4 \times 10^5 Pa

now we have

3.16 \times 10^{-5} = \frac{1}{2}(1.2)P_o^2\frac{340^3}{(1.4\times 10^5)^2}

P_o = 0.162 Pa

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Sedimentary rock turns into magnum through which process
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