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rjkz [21]
3 years ago
11

A metal object with a mass of 19g is heated to 96c, then transferred to a calorimeter containg 75g of water at 18c. the water an

d metal object reach a final temperature of 22c.
a. what is the specific heat of this metal object?
Physics
2 answers:
avanturin [10]3 years ago
6 0

Let us say that Cp is the specific heat of the metal object. Then we do a heat balance (heat lost by metal = heat gained by water):

- 19g * Cp * (22degC – 96degC) = 75g * 4.184J/g degC * (22degC – 18degC)

<span>Cp = 0.893 J/g degC</span>

sasho [114]3 years ago
4 0

Answer;


Specific heat of the metal object  = 0.893 J/g°C  

Explanation and solution;

Quantity of heat = mass × specific heat capacity × change in temperature

ΔQ = Mcθ

Heat lost by the metal object = Heat gained by water

Heat lost by the metal object

= Mass of the metal object × specific heat of the metal ×change in temp

= 19 x specific heat ×( 22 - 96)

= 1406 × specific heat

Heat gained by water

= Mass of water × specific heat capacity of water × change in temperature

= 75 x 4.186 x ( 22 - 18)  

= 1255.8  J

Therefore;

= 1406 x specific heat = 1255.8  


Specific heat = 0.893 J/g°C  


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stira [4]

Answer:

3.64×10⁸ m

3.34×10⁻³ m/s²

Explanation:

Let's define some variables:

M₁ = mass of the Earth

r₁ = r = distance from the Earth's center

M₂ = mass of the moon

r₂ = d − r = distance from the moon's center

d = distance between the Earth and the moon

When the gravitational fields become equal:

GM₁m / r₁² = GM₂m / r₂²

M₁ / r₁² = M₂ / r₂²

M₁ / r² = M₂ / (d − r)²

M₁ / r² = M₂ / (d² − 2dr + r²)

M₁ (d² − 2dr + r²) = M₂ r²

M₁d² − 2dM₁ r + M₁ r² = M₂ r²

M₁d² − 2dM₁ r + (M₁ − M₂) r² = 0

d² − 2d r + (1 − M₂/M₁) r² = 0

Solving with quadratic formula:

r = [ 2d ± √(4d² − 4 (1 − M₂/M₁) d²) ] / 2 (1 − M₂/M₁)

r = [ 2d ± 2d√(1 − (1 − M₂/M₁)) ] / 2 (1 − M₂/M₁)

r = [ 2d ± 2d√(1 − 1 + M₂/M₁) ] / 2 (1 − M₂/M₁)

r = [ 2d ± 2d√(M₂/M₁) ] / 2 (1 − M₂/M₁)

When we plug in the values, we get:

r = 3.64×10⁸ m

If the moon wasn't there, the acceleration due to Earth's gravity would be:

g = GM / r²

g = (6.672×10⁻¹¹ N m²/kg²) (5.98×10²⁴ kg) / (3.64×10⁸ m)²

g = 3.34×10⁻³ m/s²

4 0
3 years ago
A body moves in a straight line. At time, it's acceleration is given by a = 12t + 1. When t =0, the velocity of the body v is 2
madreJ [45]

Answer:

v = 6t² + t + 2, s = 2t³ + ½ t² + 2t

59 m/s, 64.5 m

Explanation:

a = 12t + 1

v = ∫ a dt

v = 6t² + t + C

At t = 0, v = 2.

2 = 6(0)² + (0) + C

2 = C

Therefore, v = 6t² + t + 2.

s = ∫ v dt

s = 2t³ + ½ t² + 2t + C

At t = 0, s = 0.

0 = 2(0)³ + ½ (0)² + 2(0) + C

0 = C

Therefore, s = 2t³ + ½ t² + 2t.

At t = 3:

v = 6(3)² + (3) + 2 = 59

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xeze [42]

<u>Answer:</u>

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Answer:

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Naddika [18.5K]

Answer:

The scientific questions here are:

<em>a) How will climate change affect forests</em>

<em>b) How did life on Earth begin</em>

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