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natulia [17]
3 years ago
6

Graham and hunter are circus performers. a cable lifts graham into the air at a constant speed of 1.5 ft/s. when graham’s arms a

re 18 ft above the ground, hunter, who is standing directly underneath graham, throws graham a ball as the cable continues to lift him higher. hunter throws the ball from a position 5 ft above the ground with an initial velocity of 24 ft/s. which system of equations can be used to model this situation?
Physics
2 answers:
IRINA_888 [86]3 years ago
6 0

Answer:

A) on Edge

Explanation:

Took the test

siniylev [52]3 years ago
3 0

Answer:

The equations are :

h = 18 + 1.5t

h = 5 + 24t - 16t^2

Explanation:

Speed = distance/time

1.5ft/s = 18ft/t

1.5t=18

The equation to determine height h= 18 + 1.5t

Graham moved another 5ft further with a velocity of 24ft/s

The equation to determine his height will be:

h= 5 + 24t -16t^2

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If I bought 59 kids off the black market in a secret door in the stalls and I sell 21 kids then ask for 81 more then 12 off the
larisa [96]

You will be left with 106 kids

<h3>Meaning of word problem</h3>

A word problem can be defined as a mathematical problem that is written in word or written in a sentence format.

In a word problem, the student is expected to decode the sentence into a mathematical expression before solving

In conclusion, You will be left with 106 kids

Learn more about word problems: brainly.com/question/13818690

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5 0
1 year ago
A 4-79 permalloy solenoid coil needs to produce a minimum inductance of 1.1 . If the maximum allowed current is 4 , how many tur
daser333 [38]

The related concept to solve this exercise is given in the expressions that the magnetic field has both as a function of the number of loops, current and length, as well as inductance and permeability. The first expression could be given as,

The magnetic field H is given as,

H = \frac{nI}{l}

Here,

n = Number of turns of the coil

I = Current that flows in the coil

l = Length of the coil

From the above equation, the number of turns of the coil is,

n = \frac{Hl}{I}

The magnetic field is again given by,

H = \frac{B}{\mu_t}

Where the minimum inductance produced by the solenoid coil is B.

We have to obtain n, that

n = \dfrac{\frac{B}{\mu_t}l}{I}

Replacing with our values we have that,

n = \dfrac{\frac{1.1Wb/m^2 }{200000}(2m)}{4mA}

n = \dfrac{(\frac{1.1Wb/m^2 }{200000})(\frac{10^4 guass}{1Wb/m^2})(2m)}{4mA(\frac{10^{-3}A}{1mA})}

n = 27.5 \approx 28

Therefore the number of turn required is 28Truns

4 0
3 years ago
In a grassland ecosystem, praying mantises catch and eat grasshoppers. However, there has been a significant decrease in the pra
Alekssandra [29.7K]

Answer:

The population will increase because grasshoppers are the prey.

Explanation:

If there has been a significant decrease in the praying mantis population in recent years. This most likely affect the grasshopper population over time by the population will increase because grasshoppers are the prey. If there is less praying mantis then grasshoppers won't be eaten as much so the population of the grasshoppers will thrive

7 0
3 years ago
Read 2 more answers
Which planet moves the fastest and which planet moves slowest? a, b, c, d, e, or f. Explain
Alisiya [41]
D is the point where the planet moves the fastest. This is because it is in the perihelion, where the planet is moving at it’s fastest pace
6 0
1 year ago
5. How much time does it take for a bird flying at a speed of 45 kilometers per hour to travel a
Lyrx [107]

Answer:

40h

Explanation:

Use the velocity formula to solve

v = \frac{d}{t}

In this question, you are given velocity v = 45km/h, and you are given a distance, d = 1800km.  Time in this question is what you'll need to find.

Start by rearranging the velocity formula, to isolate for t.

v = \frac{d}{t}

Start by multiplying both sides by t

v(t) = \frac{d}{t}(t)\\\\vt = d

Then divide both sides by v.

vt\frac{1}{v} = d/v\\ \\t = \frac{d}{v}

Now that you've isolated for time, sub in your values and calculate.

t = \frac{d}{v} = \frac{1800km}{45km/h} = 40 h

8 0
2 years ago
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