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natulia [17]
3 years ago
6

Graham and hunter are circus performers. a cable lifts graham into the air at a constant speed of 1.5 ft/s. when graham’s arms a

re 18 ft above the ground, hunter, who is standing directly underneath graham, throws graham a ball as the cable continues to lift him higher. hunter throws the ball from a position 5 ft above the ground with an initial velocity of 24 ft/s. which system of equations can be used to model this situation?
Physics
2 answers:
IRINA_888 [86]3 years ago
6 0

Answer:

A) on Edge

Explanation:

Took the test

siniylev [52]3 years ago
3 0

Answer:

The equations are :

h = 18 + 1.5t

h = 5 + 24t - 16t^2

Explanation:

Speed = distance/time

1.5ft/s = 18ft/t

1.5t=18

The equation to determine height h= 18 + 1.5t

Graham moved another 5ft further with a velocity of 24ft/s

The equation to determine his height will be:

h= 5 + 24t -16t^2

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SP1b.
nata0808 [166]

Answer:

2 m/s^2, west

Explanation:

Vf=final velcoity

Vi=initial velocity

t=timw

a =  \frac{vf - vi}{t}

=

\frac{15 - 25}{5}

= - 2 m/s^2

The - changes direction and makes it opposite

2 m/s, west

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3 years ago
A rock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft. write a quadratic function equation
Andrei [34K]
During upward projection the final velocity is zero, and the gravitational acceleration is -10 m/s² (against the gravity).
Therefore; using the equation;
S = 1/2gt² + ut
Where s is the height h, g is gravitational acceleration, and t is the time and u is the initial velocity u, is 16 ft/s.
Thus; h= 1/2(-10)t² + 16t
We get; h = -5t² + 16t
Therefore; the quadratic equation is 5t² - 16t + h =0
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