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Tanzania [10]
3 years ago
12

What is the oxidation state of each element in the species Mn(ClO4)3? I'm going over oxi-redox reactions from a long time ago an

d I'm trying to remember properly.
Mn=3+
Cl=7+
and oxygen=2- right?
Chemistry
1 answer:
MA_775_DIABLO [31]3 years ago
8 0
The following are the answers:
 =oxygen  equals to a charge of 2-
number of atoms is -24
=Mn equals to the charge of +3
Mn=  3+3x-24=0
let x be the charge of Cl, so:
23-3=3x
20/3=x
=6.67 or 7
x= 7
= Cl has a charge of +7

You are right about your answers

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The answer is "= 0.078 \ kg \ H_2".

Explanation:

calculating the moles in CH_4 =\frac{PV}{RT}

                                                =\frac{(0.58 \ atm) \times (923 \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(232^{\circ} C +273)}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(505)K}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (41.4605 \frac{L \cdot atm}{mol})}\\\\= 12.9 \ mol

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CH_4 +H_2O \to  3H_2+ CO \ (g)

Calculating the amount of H_2 produced:

= 12.9 \ mol CH_4 \times  \frac{3 \ mol \ H_2 }{1 \ mol \ CH_4}\times \frac{2.016 g H_2}{1 \ mol \ H_2}\\\\= 78 \ g \ H_2 \\\\= 0.078 \ kg \ H_2

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