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german
3 years ago
14

Based on the nebular Theory, which of these is a step in the formation of a new planetary system?

Chemistry
2 answers:
never [62]3 years ago
8 0
A. evaporation of water
AveGali [126]3 years ago
4 0
The correct answer would be A: evaporation of water
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In the reaction of sodium and oxygen, which atom is the reducing agent?
pishuonlain [190]
Sodium is the reducing agent because a reducing agent is always the donor of electrons.
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3 years ago
Suppose that, from measurements in a microscope, you determine that a certain layer of graphene covers an area of 2.60μm2. conve
garri49 [273]
Given that 1 micrometer or micron (um) is equivalent by definition to 1 x 10^-6 m, this means that 1 square micron (um^2) is equivalent to (1 x 10^-6)^2 m^2, or 1 x 10^-12 m^2.

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3 years ago
Read 2 more answers
What was a Parthian battery?
timama [110]

Answer:

Scientists believe the batteries (if that is their correct function) were used to electroplate items such as putting a layer of one metal (gold) onto the surface of another (silver), a method still practiced in Iraq today.

Explanation:

8 0
4 years ago
Consider 2H2 + O2 → 2H2O. To produce 1.2 g water, how many grams of H2 are required? Report to the correct number of significant
Elden [556K]

Answer:

0.133 mol (corrected to 3 sig.fig)

Explanation:

Take the atomic mass of H=1.0, and O=16.0,

no. of moles = mass / molar mass

so no. of moles of H2O produced = 1.2 / (1.0x2+16.0)

= 0.0666666 mol

From the equation, the mole ratio of H2:H2O = 2:2 = 1:1,

meaning every 1 mole of H2 reacted gives out 1 mole of water.

So, the no, of moles of H2 required should equal to the no, of moles of H2O produced, which is also  0.0666666 moles.

mass = no. of moles x molar mass

hence,

mass of H2 required = 0.066666666 x (1.0x2)

= 0.133 mol (corrected to 3 sig.fig)

3 0
3 years ago
Smog is a type of air pollution. It is a mixture of fog and smoke or other Airborne pollutants such as exhaust fumes. What is a
Tanya [424]
The answer is acid rain 

for study island your welcome :)
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3 years ago
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