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DiKsa [7]
4 years ago
6

Knowing that a 0.90-kg object weighs 9.0 N , find the acceleration of a 0.90-kg stone in free fall . Express your answer to two

significant figures and include the appropriate units.
Physics
1 answer:
sasho [114]4 years ago
7 0

Answer:

The value of acceleration of a stone in free fall is 10\ m/s^2.

Explanation:

Given that,

Mass of the object, m = 0.9 kg

Weight of the object, W = 9 N

We need to find the acceleration of a stone in free fall. The weight of an object is given by :

W = mg

g is the acceleration of the stone in free fall

So, g=\dfrac{W}{m}

g=\dfrac{9\ N}{0.9\ kg}

g=10\ m/s^2

So, the value of acceleration of a stone in free fall is 10\ m/s^2. Hence, this is the required solution.

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3 years ago
A 1.5 kg orange falls from a tree and hits the ground in 0.75s. What is the speed of the orange just before it hits the ground?
Olenka [21]

The final speed of the orange is 7.35 m/s

Explanation:

The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. So we can use the following suvat equation:

v=u+at

where

v is the  final velocity

u is the initial velocity

a is the acceleration

t is the time elapsed

For the orange in this problem, we have

u = 0 (it is dropped from rest)

a=g=9.8 m/s^2 is the acceleration

Substituting t = 0.75 s, we find the final velocity (and speed) of the orange:

v=0+(9.8)(0.75)=7.35 m/s

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

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#LearnwithBrainly

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