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DiKsa [7]
3 years ago
6

Knowing that a 0.90-kg object weighs 9.0 N , find the acceleration of a 0.90-kg stone in free fall . Express your answer to two

significant figures and include the appropriate units.
Physics
1 answer:
sasho [114]3 years ago
7 0

Answer:

The value of acceleration of a stone in free fall is 10\ m/s^2.

Explanation:

Given that,

Mass of the object, m = 0.9 kg

Weight of the object, W = 9 N

We need to find the acceleration of a stone in free fall. The weight of an object is given by :

W = mg

g is the acceleration of the stone in free fall

So, g=\dfrac{W}{m}

g=\dfrac{9\ N}{0.9\ kg}

g=10\ m/s^2

So, the value of acceleration of a stone in free fall is 10\ m/s^2. Hence, this is the required solution.

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A closed system.

Explanation:

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7 0
3 years ago
Starting from rest, a disk rotates about its central axis with constant angular acceleration. In 5.00 s, it rotates 13.9 rad. Du
alisha [4.7K]

Answer:

(a) Angular acceleration is 1.112 rad/s².

(b) Average angular velocity is 2.78 rad/s .

Explanation:

The equation of motion in Rotational kinematics is:

θ = θ₀ + 0.5αt²

Here θ is angular displacement at time t, θ₀ is angular displacement at time t=0, t is time and α is constant angular acceleration.

(a) According to the problem, θ is 13.9 rad, θ₀ is zero as it is at rest and t is 5 s. Put these values in the above equation:

13.9 = 0 + 0.5α(5)²

α = 1.112 rad/s²

(b) The equation of average angular velocity is:

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