Answer:
Macronutrients are simply nutrients the body needs in a very high amount e.g Carbohydrate.
MicroNutrients are simply nutrients the body needs but in little amount e.g Minerals.
Explanation:
So for further breakdown:
What are nutrients? Nutrients are essential elements that nourish the body in different capacities. We as humans get most of out nutrients from the food and water we ingest.
Now about Macro Nutrients: From the prefix "Macro" which means large, we can infer that macro nutrients are elements need by the body for the fundamental processes of the body, deficiency in this nutrients are very easy to spot. Examples are: Carbohydrates, Protein, Fats amd Water.
Micro Nutrients: In relation to macro nutrients this are elements that the body needs but are not needed in Large quantities. They mostly work like supporting nutrients. Most chemical activities like reaction that occur in the body are a function of micro nutrients. Defiencies in micrp nutrients may take some time to spot e.g Minerals and Vitamins
In regards to exercise: Macro nutrients are the essential ones here since they are the ones that generate energy. PS: micro nutrients dont generate energy.
In regards to rest: Both the Macro and Micro Nutrients are essentail for the overall well being of the body.
Answer:
V = 0.5 m/s
Explanation:
given data:
width of channel = 4 m
depth of channel = 2 m
mass flow rate = 4000 kg/s = 4 m3/s
we know that mass flow rate is given as
![\dot{m}=\rho AV](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%3D%5Crho%20AV)
Putting all the value to get the velocity of the flow
![\frac{\dot{m}}{\rho A} = V](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cdot%7Bm%7D%7D%7B%5Crho%20A%7D%20%3D%20V)
![V = \frac{4000}{1000*4*2}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4000%7D%7B1000%2A4%2A2%7D)
V = 0.5 m/s
Answer:
The tube surface temperature immediately after installation is 120.4°C and after prolonged service is 110.8°C
Explanation:
The properties of water at 100°C and 1 atm are:
pL = 957.9 kg/m³
pV = 0.596 kg/m³
ΔHL = 2257 kJ/kg
CpL = 4.217 kJ/kg K
uL = 279x10⁻⁶Ns/m²
KL = 0.68 W/m K
σ = 58.9x10³N/m
When the water boils on the surface its heat flux is:
![q=0.149h_{fg} \rho _{v} (\frac{\sigma (\rho _{L}-\rho _{v})}{\rho _{v}^{2} } )^{1/4} =0.149*2257*0.596*(\frac{58.9x10^{-3}*(957.9-0.596) }{0.596^{2} } )^{1/4} =18703.42W/m^{2}](https://tex.z-dn.net/?f=q%3D0.149h_%7Bfg%7D%20%5Crho%20_%7Bv%7D%20%28%5Cfrac%7B%5Csigma%20%28%5Crho%20_%7BL%7D-%5Crho%20_%7Bv%7D%29%7D%7B%5Crho%20_%7Bv%7D%5E%7B2%7D%20%7D%20%20%29%5E%7B1%2F4%7D%20%3D0.149%2A2257%2A0.596%2A%28%5Cfrac%7B58.9x10%5E%7B-3%7D%2A%28957.9-0.596%29%20%7D%7B0.596%5E%7B2%7D%20%7D%20%29%5E%7B1%2F4%7D%20%3D18703.42W%2Fm%5E%7B2%7D)
For copper-water, the properties are:
Cfg = 0.0128
The heat flux is:
qn = 0.9 * 18703.42 = 16833.078 W/m²
![q_{n} =uK(\frac{g(\rho_{L}-\rho _{v}) }{\sigma })^{1/2} (\frac{c_{pL}*deltaT }{c_{fg}h_{fg}Pr } \\16833.078=279x10^{-6} *2257x10^{3} (\frac{9.8*(957.9-0.596)}{0.596} )^{1/2} *(\frac{4.127x10^{3}*delta-T }{0.0128*2257x10^{3}*1.76 } )^{3} \\delta-T=20.4](https://tex.z-dn.net/?f=q_%7Bn%7D%20%3DuK%28%5Cfrac%7Bg%28%5Crho_%7BL%7D-%5Crho%20_%7Bv%7D%29%20%20%20%20%20%7D%7B%5Csigma%20%7D%29%5E%7B1%2F2%7D%20%28%5Cfrac%7Bc_%7BpL%7D%2AdeltaT%20%7D%7Bc_%7Bfg%7Dh_%7Bfg%7DPr%20%20%7D%20%5C%5C16833.078%3D279x10%5E%7B-6%7D%20%2A2257x10%5E%7B3%7D%20%28%5Cfrac%7B9.8%2A%28957.9-0.596%29%7D%7B0.596%7D%20%29%5E%7B1%2F2%7D%20%2A%28%5Cfrac%7B4.127x10%5E%7B3%7D%2Adelta-T%20%7D%7B0.0128%2A2257x10%5E%7B3%7D%2A1.76%20%7D%20%29%5E%7B3%7D%20%5C%5Cdelta-T%3D20.4)
The tube surface temperature immediately after installation is:
Tinst = 100 + 20.4 = 120.4°C
For rough surfaces, Cfg = 0.0068. Using the same equation:
ΔT = 10.8°C
The tube surface temperature after prolonged service is:
Tprolo = 100 + 10.8 = 110.8°C
Answer:
4. A series of steps engineers use to solve problems.
Explanation:
The process of engineering design is a sequence of procedures that engineers pursue to arrive at a solution to a specific problem. Most times the solution includes creating a product such as a computer code, which fulfills certain conditions or performs a function. If the project in-hand includes designing, constructing, and testing it, then engineers probably adopt the design process. Steps of the process include defining the problem, doing background research, specifying requirements, brainstorming solutions, etc.
Answer: Option D is not true of hydraulic valves. A hydraulic valve is a device that can change the opening degree of liquid flow path
Explanation:
The pilot check valve allows flow of liquid in one direction and blocks flow in the opposite direction