Question

a quantity of zinc reacts with sulfuric acid and produces 0.10g of hydrogen. how many particles of zinc are required socratic.org?

Answer 1

Answer:

grams of zinc required = 3.24 g

Particles of zinc required = $2.99\times 10^{22}$

Explanation:

Given that:-

Mass of hydrogen gas produced = 0.10 g

Calculation of the moles of $H_2$ as:-

Mass = 0.10 g

Molar mass of $H_2$ = 2.016 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{0.10\ g}{2.016\ g/mol}$

$Moles= 0.0496\ mol$

According to the reaction shown below:-

$Zn+H_2SO_4\rightarrow ZnSO_4+H_2$

1 mole of hydrogen gas is produced when 1 mole of zinc reacts

So,

0.0496 mole of hydrogen gas is produced when 0.0496 mole of zinc reacts

Moles of Zinc required = 0.0496 moles

Molar mass of zinc = 65.38 g/mol

mass= Moles*Molar mass = $0.0496\ moles\times 65.38\ g/mol=3.24\ g$

Also, 1 mole of Zinc contains $6.023\times 10^{23}$ particles

0.0496 mole of Zinc contains $0.0496\times 6.023\times 10^{23}$ particles

Particles of zinc required = $2.99\times 10^{22}$