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mina [271]
4 years ago
6

a waitperson pushes the bottom of a glass tumbler full of water across a tabletop at a constant speed. The tumbler and its conte

nts have a mass of 0.70kg, and the coefficient of kinetic friction for the surfaces in contact is 0.41. What force does the waitperson exert on the glass?
Physics
1 answer:
bekas [8.4K]4 years ago
4 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

 <span>Constant speed, therefore net force in the x direction must = 0. 

Find normal foce: 

Fnet in the y direction is equal to 0. 

0 = Fn - Fg 
Fn = 0.70 (9.81) 
Fn = 6.867 N 

x direction: 

Fnet = Fapp - Ff 
0 = Fapp - mu(Fn) 
Fapp = 0.41(6.867) 
Fapp = 2.81547 N</span>
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3 years ago
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Suppose that you are standing on a train accelerating at 0.20g. What minimum coefficient of static friction must exist between y
Ilia_Sergeevich [38]
Acceleration = (0.2 x g) = 1.96m/sec^2. 
<span>Accelerating force on 1kg. = (ma) = 1.96N. </span>
<span>1kg. has a weight (normal force) of 9.8N. </span>
<span>Coefficient µ = 1.96/9.8 = 0.2 minimum. </span>

<span>Coefficient is a ratio, so holds true for any value of mass to find accelerating force acting. </span>
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5 0
4 years ago
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A car starts from rest with an acceleration of 2.84 m/s2 at the instant when a second car moving with a velocity of 25.7 m/s pas
vredina [299]

Answer:

464.69 m

Explanation:

First car

s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times t+\frac{1}{2}2.84t^2\\\Rightarrow s=1.42t^2

Second car

Distance = Speed × Time

\text{Distance}=25.7t

Here, the time taken and the distance traveled will be the same

Equating the two equations

1.42t^2=25.7t\\\Rightarrow t=\frac{25.7}{1.42}\\\Rightarrow t=18.09\ s

So, the first would have to move 1.42t^2=1.42\times 18.09^2=464.69\ m in order to overtake the second car.

7 0
3 years ago
Based on the information in the table, which elements are most likely in the same periods of the periodic table?
irinina [24]

Answer:

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6 0
3 years ago
You measure the power delivered by a battery to be 5.83 W when it is connected in series with two equal resistors. How much powe
BabaBlast [244]

Answer:

P = 23.32 W

Explanation:

In series  

equivalent Resistance

R(eq)=R+R=2R

In parallel equivalent resistance

R(eq) = R*R/(R+R) =R/2

since.

power

P=V² / R

in series

⇒V = √(P*R)

=√(5.83*2R )

=√(11.66R)

in parallel

P = V² / R(eq)

=(√(11.66R)²) / (R/2)

P=11.66 * R * 2/R

P = 23.32 W

6 0
3 years ago
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