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mina [271]
4 years ago
6

a waitperson pushes the bottom of a glass tumbler full of water across a tabletop at a constant speed. The tumbler and its conte

nts have a mass of 0.70kg, and the coefficient of kinetic friction for the surfaces in contact is 0.41. What force does the waitperson exert on the glass?
Physics
1 answer:
bekas [8.4K]4 years ago
4 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

 <span>Constant speed, therefore net force in the x direction must = 0. 

Find normal foce: 

Fnet in the y direction is equal to 0. 

0 = Fn - Fg 
Fn = 0.70 (9.81) 
Fn = 6.867 N 

x direction: 

Fnet = Fapp - Ff 
0 = Fapp - mu(Fn) 
Fapp = 0.41(6.867) 
Fapp = 2.81547 N</span>
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777dan777 [17]
5.625 hours and it is 450 divided by 80
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4 0
3 years ago
What is inertia? That is all but I need 20 characters to ask lol
damaskus [11]
Inertia, property of a body by virtue of which it opposes any agency that attempts to put it in motion or, if it is moving, to change the magnitude or direction of its velocity. Inertia is a passive property and does not enable a body to do anything except oppose such active agents as forces and torques.
8 0
3 years ago
A launched hopper reach to 1.20 m maximum height. How much is it’s launch velocity?
garri49 [273]

The launch velocity is 4.8 m/s

Explanation:

We can solve this problem by applying the law of conservation of energy. In fact, the mechanical energy of the hopper (equal to the sum of the potential energy + the kinetic energy) is conserved. So we can write:

U_i +K_i = U_f + K_f

where:

U_i is the initial potential energy, at the bottom

K_i is the initial kinetic energy, at the bottom

U_f is the final potential energy, at the top

K_f is the final kinetic energy, at the top

We can rewrite the equation as:

mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2

where:

m is the mass of the hopper

g=9.8 m/s^2 is the acceleration of gravity

h_i = 0 is the initial height

u is the launch speed of the hopper

h_f = 1.20 m is the maximum altitude reached by the hopper

v = 0 is the final speed (which is zero when the hopper reaches the maximum height)

Solving the equation for u, we find the launch speed of the hopper:

u=\sqrt{2gh_g}=\sqrt{2(9.8)(1.20)}=4.8 m/s

Learn more about kinetic energy and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647  

brainly.com/question/10770261  

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4 0
3 years ago
Two large non-conducting plates of surface area A = 0.25 m 2 carry equal but opposite charges What is the energy density of the
Stells [14]

Answer:

5.1*10^3 J/m^3

Explanation:

Using E = q/A*eo

And

q =75*10^-6 C

A = 0.25

eo = 8.85*10^-12

Energy density = 1/2*eo*(E^2) = 1/2*eo*(q/A*eo)^2 = [q^2] / [2*(A^2)*eo]

= [(75*10^-6)^2] / [2*(0.25)^2*8.85*10^-12]

= 5.1*10^3 J/m^3

8 0
3 years ago
A speaker vibrates at a frequency of 200 Hz. What is its period
Daniel [21]
Period,  T = 1/ f.
f = frequency =  200 Hz.

Period T =  1/200 =  0.005 seconds.
8 0
3 years ago
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