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kipiarov [429]
3 years ago
9

for hydrogen-like atom classify these electron transitions by whether they result in absorption or emission light n=3 to n=5 and

n=3 to n=2
Chemistry
1 answer:
iren [92.7K]3 years ago
7 0
For hydrogen-like atom electron transition from n=3 to n=5, it would be classified as an absorption of energy. For hydrogen-like atom electron transition from <span>n=3 to n=2, it would be classified as an emission of energy. Hope this helps. Have a nice day.</span>
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Which of the following chemical reactions is an oxidation-reduction reaction? CuSO4 + BaCl2 yields BaSO4 + CuCl2 Pb(NO3)2 + 2NaC
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Given that, an experiment to measure the enthalpy change for the reaction of aqueous copper(II) sulfate, CuSO4(aq) and zinc, Zn(s) was carried out in a coffee cup calorimeter; the heat of the reaction in the whole system is calculated to be 2218.34 kJ

Heat of reaction (i.e enthalpy of reaction) is the quantity of heat that is required to be added or removed when a chemical reaction is taken place in order to maintain all of the compounds present at the same temperature.

The formula used to calculate the heat of the reaction can be expressed as follows:

Q = mcΔT

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From the information given:

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The change in temperature i.e. ΔT = T₂ - T₁

ΔT = 91.5° C - 25° C

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The number of moles of CuSO₄ = 1.00 mol/dm³ × 50.0 cm³

\mathbf{= (1 \times \dfrac{50}{1000})\ moles}

= 0.05 moles

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Then;

Using the relation:

\mathbf{number \ of \ moles = \dfrac{mass}{molar \ mass}}}

By crossing multiplying;

mass of CuSO₄ = number of moles of CuSO₄ ×  molar mass of CuSO₄

mass of CuSO₄ = 0.05 moles  × 159.609 g/moles

mass of CuSO₄ = 7.9805 grams

∴

Using the formula from above:

Q = mcΔT

Q = 7.9805 g × 4.18 kJ/g °C × 66.5° C

Q = 2218.34 kJ

Therefore, we can conclude that the heat of the reaction is 2218.34 kJ

Learn more about the chemical reaction here:

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