1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kipiarov [429]
3 years ago
9

for hydrogen-like atom classify these electron transitions by whether they result in absorption or emission light n=3 to n=5 and

n=3 to n=2
Chemistry
1 answer:
iren [92.7K]3 years ago
7 0
For hydrogen-like atom electron transition from n=3 to n=5, it would be classified as an absorption of energy. For hydrogen-like atom electron transition from <span>n=3 to n=2, it would be classified as an emission of energy. Hope this helps. Have a nice day.</span>
You might be interested in
Which family contains elements with a full octet of valence electrons?
iren [92.7K]
D. the noble gasses !!!!
5 0
4 years ago
Read 2 more answers
Help me Please<br><br> Is boiling an egg a physical or a chemical change? Explain your answer.
Blababa [14]

Answer:

it's a chemistry change

Explanation:

this is because heat is causing permanent changes and can no longer be changed back to its original atate

6 0
2 years ago
Describe how differences in temperatures cause the convection process in oceans.
Ilia_Sergeevich [38]

Answer:

The higher the temperature the more water evaporates and that affects the convection process

Explanation:

3 0
3 years ago
Read 2 more answers
A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.
Lubov Fominskaja [6]

Answer:

Ag_2SO_4

Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

Ag, \frac{0.05305}{0.02657} \approx 2

S, \frac{0.02657}{0.02657} \approx 1

O, \frac{0.10594}{0.02657} \approx 4

Therefore, empirical formula of the compound = Ag_2SO_4

7 0
4 years ago
Read 2 more answers
How many grams of sulfur are needed to react completely with 246 g of mercury to form hgs?
iren [92.7K]

The reaction between mercury (Hg) and sulfur (S) to form HgS is:

Hg + S ------------- HgS

Therefore: 1 mole of Hg reacts with 1 mole of S to form 1 mole of HgS

The given mass of Hg = 246 g

Atomic mass of Hg = 200.59 g/mol

# moles of Hg = 246 g/ 200.59 gmol-1 = 1.226 moles

Based on the reaction stoichiometry,

# moles of S that would react = 1.226 moles

Atomic mass of S = 32 g/mol

Therefore, mass of S = 1.226 moles*32 g/mole = 39.23 g

39.2 g of sulfur would be needed to react completely with 246 g of Hg to produce HgS

5 0
3 years ago
Read 2 more answers
Other questions:
  • What is the number of carbon atoms in the ring portion of the haworth structure of glucose?
    15·1 answer
  • The largest group of organisms that is capable of interbreeding is?
    12·1 answer
  • How many moles are equal to 1.4 x 10^24 atoms of aluminum
    5·1 answer
  • What will for if sodium give away one electron ?
    6·1 answer
  • A 0.100 mile sample of gas is at a temperature of 85.0 degrees C and a volume of 3.47 L. What is the pressure of the gas( in mm
    12·1 answer
  • Pure Gold (24 Kt) is a soft metal, so jewelers often add other metals (silver or copper) to make gold rings harder (and less exp
    14·1 answer
  • What term refers to the elements in a column of the periodic table
    8·1 answer
  • This is a graph of the mean, or average, number of
    14·1 answer
  • Give 3 examples of conduction, radiation, and convection.
    14·2 answers
  • Someone please help me figure out the significant figure
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!