What happens when a boxer doesn't make weight?

Physics

1 answer:

ryzh [129]4 years ago

6 0

They would just have to box in a higher weight class

You might be interested in

A rubber ball and a steel ball are dropped from the same height onto a concrete floor. They have the same mass, and lets assume

Mkey [24]

Answer:

The average forces would be the same

Explanation:

Both have the same velocity on impact as they fell from the same height.

Both have the same velocity after the bounce because they reach the same height.

Both have the same mass

Both will thus experience the same impulse because both have the same change in momentum.

Therefore both experience the same average force.

5 0

3 years ago

During a hot summer drought, an area receives very little rain. The animals that live in the area will probably A. decrease in n

meriva

Answer: I believe the right answer would be C

I hope this helps. Correct me if im wrong

5 0

3 years ago

Read 2 more answers

A car starts from rest and moves along the positive x-axis with a constant acceleration of 5 m/s/s for 8 seconds. It then contin

tino4ka555 [31]

Answer:

340

Explanation:

Because you are moving at 5 m/s^2 for 8 seconds, you need to do some arithmetic to get the distance covered in the beginning. TO do this, you do 5 + 5*2 + 5*3 + 5*4 + 5*5 + 5*6 + 5*7 + 5*8, and once you have passed eight seconds, you need 4 more seconds with constant velocity, or 4(5*8). Your final equation would be 5+10+15+20+25+30+35+40+40+40+40+40. Hope this helps!

5 0

3 years ago

Read 2 more answers

A ray of light incident in air strikes a rectangular glass block of refractive index 1.50, at an angle of incidence of 45°. Calc

balandron [24]

Answer:

Approximately $28^{\circ}$ .

Explanation:

The refractive index of the air $n_{\text{air}}$ is approximately $1.00$ .

Let $n_\text{glass}$ denote the refractive index of the glass block, and let $\theta _{\text{glass}}$ denote the angle of refraction in the glass. Let $\theta_\text{air}$ denote the angle at which the light enters the glass block from the air.

By Snell's Law:

$n_{\text{glass}} \, \sin(\theta_{\text{glass}}) = n_{\text{air}} \, \sin(\theta_{\text{air}})$ .

Rearrange the Snell's Law equation to obtain:

$\begin{aligned} \sin(\theta_{\text{glass}}) &= \frac{n_{\text{air}} \, \sin(\theta_{\text{air}})}{n_{\text{glass}}} \\ &= \frac{(1.00)\, (\sin(45^{\circ}))}{1.50} \\ &\approx 0.471\end{aligned}$ .