Question

A load consists of a 70-Ω resistor in parallel with a 90-μF capacitor. If the load is connected to a voltage source vs(t) = 160cos 2000t, find the average power delivered to the load.

Answer 1

Answer:

Power delivered by the source will be 182.912 watt

Explanation:

We have given a load is consist of a resistor of 70 ohm in parallel with $90\mu F$ capacitance

Voltage source is given $v_s(t)=160cos(2000t)$

So maximum value of voltage source is 160 volt

So rms value $v_{r}=\frac{v_m}{\sqrt{2}}=\frac{160}{1.414}=113.154volt$

We know that average power delivered by the source will be equal to average power absorbed by the resistor

So power absorbed by the resistor $P=\frac{v_r^2}{R}=\frac{113.154^2}{70}=182.912watt$

So power delivered by the source will be 182.912 watt