Answer:
The distance can the water be projected is 4.51 m
Explanation:
The speed of the water in the hose is equal to:
v1 = R/A1
If we solve the continuity for v2:
v2 = R/A2 (eq. 1)
The equation for the vertical position is:
yf = yi + vy*t - (1/2)gt²
yi = 0
vy = 0
Clearing t:
(eq. 2)
The equation for position is:
xf = xi + vxt = 0 + v2t = v2t (eq. 3)
Replacing equation 1 and 2 in equation 3:
![x_{f} =\frac{R}{A_{2} } \sqrt{\frac{-2y_{f} }{g} } =\frac{30}{0.5} \sqrt{\frac{(-2)*(-1)}{9.8} }*\frac{1000}{60} =451.75cm=4.51m](https://tex.z-dn.net/?f=x_%7Bf%7D%20%3D%5Cfrac%7BR%7D%7BA_%7B2%7D%20%20%7D%20%5Csqrt%7B%5Cfrac%7B-2y_%7Bf%7D%20%7D%7Bg%7D%20%7D%20%3D%5Cfrac%7B30%7D%7B0.5%7D%20%5Csqrt%7B%5Cfrac%7B%28-2%29%2A%28-1%29%7D%7B9.8%7D%20%7D%2A%5Cfrac%7B1000%7D%7B60%7D%20%20%3D451.75cm%3D4.51m)
Answer:
I think it is False.
Explanation:
I think that a body could not be vertical for every time.
Answer:
123.61 J
Explanation:
PE = KE
mgh = 1/2 mv2.
(2.80)(9.81)(4.50)=123.606J
Answer:
16km/h
Explanation:
Vt=20km/h ---train speed
Vd=4km/h
Donas speed relative to ground is:
Vrd=Vt-Vd
Donas is moving in opposite direction of train .
Vrd=20km/h-4km/h
Vrd=16km/h