Explanation:
The overall rate of a reaction between two species doubles when: the order of both species changes or any of the species changes.
The overall order of the reaction is found by adding up the individual orders. For example, if the reaction is first order with respect to both A and B (a = 1 and b = 1), the overall order is 2. Therefore overall order is 2 or second order reaction although order of individual species is 1.
"players on a field that has a maximum of 15 players" would be the best option from the list regarding an analogy that best represents a saturated solution
<span>an empty baseball field.</span>
Answer: The heat needed to be removed to freeze 45.0 g of water at 0.0 °C is 15.01 KJ.
Explanation:
- Firstly, we need to define the term <em>"latent heat"</em> which is the amount of energy required "absorbed or removed" to change the phase "physical state; solid, liquid and vapor" without changing the temperature.
- Types of latent heat: depends on the phases that the change occur between them;
- Liquid → vapor, <em>latent heat of vaporization</em> and energy is absorbed.
- Vapor → liquid, latent heat of liquification and the energy is removed.
- Liquid → solid, <em>latent heat of solidification</em> and the energy is removed.
- Solid → liquid, <em>latent heat of fusion</em> and the energy is absorbed.
- In our problem, we deals with latent heat of freezing "solidification" of water.
- The latent heat of freezing of water, ΔHf, = 333.55 J/g; which means that the energy required to be removed to convert 1.0 g of water from liquid to solid "freezing" is 333.55 g at 0.0 °C.
- Then the amount of energy needed to be removed to freeze 45.0 g of water at 0.0 °C is (ΔHf x no. of grams of water) = (333.55 J/g)(45.0 g) = 15009.75 J = 15.01 KJ.
Answer:
Pb(s)------>Pb2+(aq)
Explanation:
If you look at the oxidation numbers Pb increases from 0 to +2 while Cu decreases from +2 to 0.Hence,Pb is the reducing agent and Cu2+ is the oxidizing agent.
Also, a thing to note is that the oxidation number of any solid is always 0.
~Hope this helps:)