Question

What is the pOH of a 2.70 x 10^-11 M Solution of lithium hydroxide (LIOH)?

Answer 1

The POH of a 2.70 x10^-11 solution of lithium hydroxide(LiOH) is 10.6

calculation

POH= -log (OH-)

write the equation for dissociation of LiOH

LiOh---> Li^+(aq) + OH-(aq)

from the equation above the ratio LiOH: OH is 1:1 therefore the concentration of OH- =2.70 x10 ^-11

that is - log (2.70 x10^-11) = 10.6