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torisob [31]
3 years ago
8

Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

is used to make the refrigerant carbon tetrafluoride, CF4 via the reaction2COF2(g)⇌CO2(g)+CF4(g), Kc=4.10If only COF2 is present initially at a concentration of 2.00 M, what concentration of COF2 remains at equilibrium?Express your answer with the appropriate units.
Chemistry
1 answer:
kvasek [131]3 years ago
4 0

Answer:

0.396 M

Explanation:

Let's consider the following reaction.

2 COF₂(g) ⇌ CO₂(g) + CF₄(g)

We can find the concentrations at equilibrium using an ICE Chart.

         2 COF₂(g) ⇌ CO₂(g) + CF₄(g)

I            2.00              0            0

C           -2x                +x          +x

E         2.00-2x            x             x

The concentration equilibrium constant (Kc) is:

Kc=4.10=\frac{[CO_{2}][CF_{4}]}{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } =(\frac{x}{2.00-2x} )^{2} \\\sqrt{4.10} = \frac{x}{2.00-2x}\\4.05-4.05x=x\\x=0.802

The concentration of COF₂ at equilibrium is:

[COF₂] = 2.00-2x = 2.00-2(0.802) = 0.396 M

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White raven [17]

Answer:

I think it is the second one

Explanation:

Because what the cold water did to the table salt, is that it separated its molecules dissolving the salt.

even though the rock salt was in hot water it was a bigger particle. But the big difference was only because the water temperature ️.

5 0
3 years ago
A student prepares a aqueous solution of trimethylacetic acid . Calculate the fraction of trimethylacetic acid that is in the di
irinina [24]

The question is incomplete, here is the complete question:

A student prepares a 0.21 mM aqueous solution of trimethylacetic acid. Calculate the fraction of trimethylacetic acid that is in the dissociated form in his solution. Express your answer as a percentage. You will probably find some useful data in the ALEKS Data resource. Round your answer to 3 significant digits.

<u>Answer:</u> The percent of dissociation of trimethylacetic acid is 19.5 %

<u>Explanation:</u>

We are given:

Concentration of trimethylacetic acid = 0.21 mM  = 0.00021 M    (Conversion factor:  1 mole = 1000 millimoles )

The chemical equation for the dissociation of trimethylacetic acid follows:

                     C_4H_9COOH\rightleftharpoons C_4H_9COO^-+H^+

<u>Initial:</u>                   0.00021

<u>At eqllm:</u>             0.00021-x              x            x

The expression of K_a for above equation follows:

K_a=\frac{[C_4H_9COO^-][H^+]}{[C_4H_9COOH]}

We know that:

K_a\text{ for }C_4H_9COOH=1\times 10^{-5}

Putting values in above expression, we get:

1\times 10^{-5}=\frac{x\times x}{(0.00021-x))}\\\\x=0.000041,-0.000051

Neglecting the negative value of 'x' because concentration cannot be negative.

To calculate the fraction of dissociation, we use the equation:

\text{Percent of dissociation}=\frac{[H^+]}{[C_4H_9COOH]}\times 100

Putting values in above equation, we get:

\text{Percent of dissociation}=\frac{0.000041}{0.00021}\times 100\\\\\text{Percent of dissociation of trimethylacetic acid}=19.5%

Hence, the percent of dissociation of trimethylacetic acid is 19.5 %

8 0
3 years ago
What is the molarity of a solution made of 2.45 moles of LiCl in 4.75 L of solution?
morpeh [17]

Answer:

.52 M

Explanation:

moles ÷ liters = molarity

2.45 ÷ 4.75 = 0.5157894737

rounding it = .52

7 0
3 years ago
Why do submarines have to be built with such strong, thick walls, compared to ships? Explain in as much detail as you can using
ankoles [38]
Ships only go a couple meters under water so their hull is not required to go so far underwater. A submarine goes much lower which means there is much more pressure on the hull which requires a bigger hull.
4 0
3 years ago
According to Frank, what is the “10 second rule"?
Lelechka [254]

Answer:

The first option, aka Opick it up off the gound within 10 seconds, and it's o.k. to eat

Explanation:

The 10 second rule is a rule when you drop foods, but if you get it off the floor under 10 seconds, you can eat it.

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4 0
3 years ago
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