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torisob [31]
3 years ago
8

Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

is used to make the refrigerant carbon tetrafluoride, CF4 via the reaction2COF2(g)⇌CO2(g)+CF4(g), Kc=4.10If only COF2 is present initially at a concentration of 2.00 M, what concentration of COF2 remains at equilibrium?Express your answer with the appropriate units.
Chemistry
1 answer:
kvasek [131]3 years ago
4 0

Answer:

0.396 M

Explanation:

Let's consider the following reaction.

2 COF₂(g) ⇌ CO₂(g) + CF₄(g)

We can find the concentrations at equilibrium using an ICE Chart.

         2 COF₂(g) ⇌ CO₂(g) + CF₄(g)

I            2.00              0            0

C           -2x                +x          +x

E         2.00-2x            x             x

The concentration equilibrium constant (Kc) is:

Kc=4.10=\frac{[CO_{2}][CF_{4}]}{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } =(\frac{x}{2.00-2x} )^{2} \\\sqrt{4.10} = \frac{x}{2.00-2x}\\4.05-4.05x=x\\x=0.802

The concentration of COF₂ at equilibrium is:

[COF₂] = 2.00-2x = 2.00-2(0.802) = 0.396 M

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what is the best course of action if solid material remains in the flask after the heating step of recrystallization
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filter the hot mixture.

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The water in a pressure cooker boils at a temperature greater than 100°C because it is under pressure. At this higher temperatur
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Answer:

the activation energy Ea = 179.176 kJ/mol

it will take  7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

Explanation:

From the given information

T_1 = 100^0 C = 100+273 = 373 \ K \\ \\  T_2 = 113^0 C = 113 + 273 = 386 \ K

R_1 = \dfrac{1}{7}

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Because at 113.0°C; the rate is 7 time higher than at 100°C

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1.9459 = \dfrac{Ea}{8.314}* 9.0292  *10^{-5}

1.9459*8.314 = Ea * 9.0292*10^{-5}

16.1782126= Ea * 9.0292*10^{-5}

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Thus; the activation energy Ea = 179.176 kJ/mol

b)

here;

T_2 = 386 \  K  \\ \\T_1 = (89.8 + 273)K = 362.8 \ K

In(\dfrac{R_2}{R_1})= \dfrac{Ea}{R}(\dfrac{1}{T_1}- \dfrac{1}{T_2})

In(\dfrac{R_2}{R_1})= \dfrac{179.176}{8.314}(\dfrac{1}{362.8}- \dfrac{1}{386})

In (\dfrac{R_2}{R_1}) = 0.00357

\dfrac{R_2}{R_1}= e^{0.00357}

\dfrac{R_2}{R_1}= 1.0035

where ;

R_2 = \dfrac{1}7{}

R_1 = \dfrac{1}{t}

Now;

\dfrac{t}{7}= 1.0035

t = 7.0245 mins

Therefore; it will take  7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

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Answer:

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