<span>The correct answer is: C) refraction.
Hope this helps :)</span>
Resistors and reactors, for use over 600 volts, shall not be installed in close enough proximity to combustible materials to constitute a fire hazard and shall have a clearance of not less than<u> 300 mm </u>from combustible materials.
Explanation:
- The hazards associated with high power industrial resistors are primarily due to their open construction, which is necessary for cooling.
- The exposed conductors which make up the resistors can be not only a shock hazard but also a thermal burn hazard.
- When a resistor fails, it either goes open or the resistance increases. When the resistance increases, it can burn the board, or burn itself up.
- Avoid touching non-flammable resistors in operation; the surface temperature ranges from approximately 350 °C to 400°C when utilized at the full rated value. Maintaining a surface temperature of 200°C or less will extend resistors service life.
- Do not apply power to a circuit while measuring resistance. When you are finished using an ohmmeter, switch it to the OFF position if one is provided and remove the leads from the meter.
- Always adjust the ohmmeter for 0 (or in shunt ohmmeter) after you change ranges before making the resistance measurement.
Answer:
a) Total distance travelled = 1.9km + 8.7km + 3.0km = 13.6km
b) Total displacement = -1.9km + 8.7km-3.0km=+3.8km
Total displacement = 3.8km due west
Explanation:
a) Total distance travelled is a scalar quantity it is not affected by the direction it's only concerned with the magnitude.
Total distance travelled = 1.9km + 8.7km + 3.0km = 13.6km
b) Total displacement is a vector quantity it takes into consideration both magnitude and direction.
Taking west as positive and east as negative.
Total displacement = -1.9km + 8.7km-3.0km = +3.8km
Total displacement = 3.8km due west
Explanation:
It is given that,
Initial speed of the automobile, u = 65 km/hr =
Final speed of the automobile, v = 0
Deceleration of the automobile, 
We need to find the distance covered by the car as it comes to rest. It can be calculated using third equation of motion as :
So, the acceleration of the car is 
. Hence, this is the required solution.
Answer:
1a.5km
2a. 31536000 seconds
2b.2800000 centimeters
2c.45,000,000 Milligrams
2d.0.0141667 m/s
2e.2.592 x 10^10 km/day
2f .8.23x10^-7m
2g.0.0000085 m3
Explanation:
1a.(25km/5)(1000m/1km)(1h/3600s) =(5km)( 1) (1) =5km
pls mark as brainliest
