Answer:
Radiation
Explanation:
The sun radiates energy to the earth to make it warmer near the equator.
Answer:
The explosive force experienced by the shell inside the barrel is 23437500 newtons.
Explanation:
Let suppose that shells are not experiencing any effect from non-conservative forces (i.e. friction, air viscosity) and changes in gravitational potential energy are negligible. The explosive force experienced by the shell inside the barrel can be estimated by Work-Energy Theorem, represented by the following formula:
(1)
Where:
- Explosive force, measured in newtons.
- Barrel length, measured in meters.
- Mass of the shell, measured in kilograms.
,
- Initial and final speeds of the shell, measured in meters per second.
If we know that
,
,
and
, then the explosive force experienced by the shell inside the barrel is:
![F = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot \Delta s}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bm%5Ccdot%20%28v_%7Bf%7D%5E%7B2%7D-v_%7Bo%7D%5E%7B2%7D%29%7D%7B2%5Ccdot%20%5CDelta%20s%7D)
![F = \frac{(1250\,kg)\cdot \left[\left(750\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (15\,m)}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B%281250%5C%2Ckg%29%5Ccdot%20%5Cleft%5B%5Cleft%28750%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%29%5E%7B2%7D-%5Cleft%280%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%29%5E%7B2%7D%5Cright%5D%7D%7B2%5Ccdot%20%2815%5C%2Cm%29%7D)
![F = 23437500\,N](https://tex.z-dn.net/?f=F%20%3D%2023437500%5C%2CN)
The explosive force experienced by the shell inside the barrel is 23437500 newtons.
Answer:
The answer is C
Explanation:
The magnitude of the gravitational force depends inversely on the square of the radial distance between the centers of the two masses. Thus, essentially, the force can only fall to zero, when the denominator that is r becomes infinite.
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